Answer:
2.07 mol O₂
Explanation:
First we need to write down the species present in the chemical equation, using the information given by the exercise:
However this equation <em>is not balanced</em>, so now we<u> balance it</u>:
Now we can use the stoichiometric ratio to <u>calculate the moles of oxygen </u>from the moles of sulfide dioxide:
- 1.38 molSO₂ *
= 2.07 mol O₂
Answer:
5-chloro-1,3-cyclopentadiene
Explanation:
5-chloro-1,3-cyclopentadiene will react more slowly in an SN1 reaction. ( i.e. No reaction as the product is unstable ) attached is the representation of the rate of reaction of both Halides which shows that 5-chloro-1,3-cyclopentadiene reacts the slowest .
Also During SN1 reaction Carbocation is formed .
Attached below is the solution explanation
Hydrogen, H
Helium, He
Lithium, Li
Beryllium, Be
Boron, B
Carbon, C
Nitrogen, N
Oxygen, O
Fluorine, F
Neon, Ne
Sodium, Na
Magnesium, Mg
Aluminum, Al
Silicon, Si
Phosphorus, P
Sulfur, S
Chlorine, Cl
Argon, Ar
Potassium, K
Calcium, Ca
Answer:

Explanation:
In this case, we have to start with the <u>chemical reaction</u>:

So, if we start with <u>10 mol of cyclohexanol</u> (
) we will obtain 10 mol of cyclohexanol (
). So, we can calculate the grams of cyclohexanol if we<u> calculate the molar mass:</u>

With this value we can calculate the grams:

Now, we have as a product 500 mL of
. If we use the <u>density value</u> (0.811 g/mL). We can calculate the grams of product:

Finally, with these values we can calculate the <u>yield</u>:
%= (405.5/820)*100 = 49.45 %
See figure 1
I hope it helps!
Answer:
The correct answer is hydrogen.
Explanation:
Stars in the main sequence will remain in the main sequence as long as their cores contain hydrogen atoms. This is because main sequence stars run on the hydrogen atoms within their core to prevent them from falling to the force of gravity. Once these hydrogen atoms run out, the star is no longer considered a main sequence star, gravity takes hold, and the star collapses.