23 times 8 divided into 3 what’s the answer?

Mathematics

1 answer:

Radda [10]2 years ago

3 0

Answer:

We take 23 times 8 which gives us 184 and now we can figure out the second part of the question is how much 184 divide into 3 is. This wording is really weird so I think it's asking for 184/3 which would give us 61.333 with the 3 repeating.

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What whole number best approximates the value of x?

ivanzaharov [21]

The answer is 87

For this problem, the method I used was more of a guess and check because I simply plugged the options into a calculator to see which one would be closest a little bit past 9.3 but not all the way 9.4

the square root of 87 is 9.32 so you would round down while the square root of 88 is 9.38 which would round up

Hope this helps :)

4 0

3 years ago

The first five terms of a sequence are 2, 5/3, 3/2, 7/5 and 4/3. what is the explicit formula?

katen-ka-za [31]

Answer:

an = (n+3)/(n+1)

Step-by-step explanation:

The sequence can be written as ...

4/2, 5/3, 6/4, 7/5, 8/6, ...

where the first numerator is n+3 and the first denominator is n+1. Each numerator and denominator increase by 1 from term to term, so the explicit formula can be written

an = (n+3)/(n+1)

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3 years ago

The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va

Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

$d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore$