The question is incomplete, here is the complete question.
A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of copper fluoride in the solution is 
<u>Explanation:</u>
To calculate the molarity of solute, we use the equation:
We are given:
Given mass of copper (II) fluoride = 0.0498 g
Molar mass of copper (II) fluoride = 101.54 g/mol
Volume of solution = 100.0 mL
Putting values in above equation, we get:
Hence, the concentration of copper fluoride in the solution is
Filtration is useful for separating sediments that are carried in water for easy drinking without the risk of disease - an example of this is a water purifier
22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
To find the mass, the given data was,
Volume = 11.6 Liters
<h3>What is decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:
2 NaN₃ ⇒ 2 Na + 3 N₂
We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.
- At STP, 1 mole of N₂ occupies 22.4 L.
- The molar ratio of N₂ to NaN₃ is 3:2.
- The molar mass of NaN₃ is 65.01 g/mol.
Substituting all the known values to find the volume,
11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)
= 22.4 g.
22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
Learn more about decomposition reaction,
brainly.com/question/8009068
#SPJ4
Answer: 19kpa
Explanation:
The total pressure of a mixture of gases is the sum of the partial pressure exacted by the individual gases.
P total = P X + P Y
From the question above:
P total = P .nitrogen + P. oxygen
123.5kpa = 104.5kpa + P. Oxygen
P. Oxygen = 123.5kpa - 104.5kpa
= 19kpa
