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CaHeK987 [17]
3 years ago
15

Uranium mining and milling waste contains low levels of :

Chemistry
1 answer:
gavmur [86]3 years ago
5 0

Answer: D

Explanation:

Uranium ore is radioactive. That means, it spontaneously emits radiation which could have a damaging effect on the tissues of living organisms.

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The number 6.02 x 1023 is
const2013 [10]

Avogadro's constant

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A student dissolves 4.5 G of sodium chloride into 75 grams of water which of the following statements is correct regarding the r
Jobisdone [24]
"The vapor pressure will decrease and the boiling temperature will increase." When sodium chloride is added to water, the vapor pressure above the resulting salt solution is less than the vapor pressure above the pure water, and the boiling point of the salt solution will be greater than the boiling point of pure water. This results from the introduction of salt molecules to water, in which the salt solution needs a higher temperature for the vapor pressure to be equal to the pressure of the atmosphere.
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What is the common name for sodium hypochlorite
Firlakuza [10]
The common name is laundry bleach

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3 0
4 years ago
A 33.6 mL solution of KCl has a mass of 27.29 g. After evaporating to dryness, the dry salt residues has a mass of 6.31 g. Calcu
bixtya [17]

For  the molarity and the  percentage of the mass of kcl are mathematically given as

%m/m = 23.1%, molarity  = 3.38M

<h3>What is the molarity?</h3>

Generally, the equation for the  percentage of the mass of kcl is mathematically given as

(mass of kcl/mass of solution)x 100

therefore

%m/m = (6.31/27.29)x100

%m/m = 23.1%

The molarity

(no of mol/ vol of sol)

molarity  = 0.0846mol/0.0250 L

molarity  = 3.38M

In conclusion, the molarity is given as

molarity  = 3.38M

Read more about Molarity

brainly.com/question/9149034

4 0
2 years ago
A student has 0.75 L of a 5.0 M solution and dilutes it to make 3.5 liters. What’s the molarity of the diluted solution?
Marianna [84]

The molarity of the diluted solution : 1.1 M

<h3>Further explanation</h3>

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

\tt n_1=n_2\\\\M_1.V_1=M_2.V_2

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=5

V₁=0.75

V₂=3.5

\tt M_2=\dfrac{M_1.V_1}{V_2}\\\\M_2=\dfrac{5\times 0.75}{3.5}\\\\M_2=1.07\approx 1.1

3 0
3 years ago
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