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IceJOKER [234]
3 years ago
15

Identify the single displacement reaction. 2H 2 + O 2 ⟶ 2H 2O Al 2S 3 ⟶ 2Al + 3S Cl 2 + 2KBr ⟶ 2KCl + Br 2 C 4H 12 + 7O 2 ⟶ 6H 2

O + 4CO 2
Chemistry
1 answer:
ozzi3 years ago
6 0

Answer: Cl_2+2KBr\rightarrow 2KCl+Br_2

Explanation:

A single displacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution. Thus one element should be different from another element.

Cl_2+2KBr\rightarrow 2KCl+Br_2

Synthesis reaction is defined as the reaction where substances combine in their elemental state to form a single compound.2H_2+O_2\rightarrow 2H_2O

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

Al_2S_3\rightarrow 2Al+3S

Combustion is a type of chemical reaction in which hydrocarbons burn in the presence of oxygen to form carbon dioxide and water along with heat.

C_4H_{12}+7O_2\rightarrow 6H_2O+4CO_2

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B

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Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d
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Answer:

             70.15 cm³

Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

Required:

                  Volume  =  ?

Formula Used:

                  Density  =  Mass ÷ Volume

Solving for Volume,

                  Volume  =  Mass ÷ Density

Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

5 0
3 years ago
if an element [x] contains 8 protons, 8 neutrons and 8 electrons, the atomic number of the element is ?
Kaylis [27]

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The atomic number refers to the number which identifies the element, which is the proton number.

7 0
3 years ago
Calculate the pH of a buffer prepared by mixing 20.0 mL of 0.10 M acetic acid and 55.0 mL of 0.10 M sodium acetate
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Calculate the pH of a buffer prepared by mixing 30.0 mL of 0.10 M acetic acid and 40.0 mL of 0.10 M sodium acetate.

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3 years ago
If a gas has a proportionality constant of 4.32 x 10-4 mol at room temperature for a particular solvent, what will the
inysia [295]

0.0467 X 10^{-4} M/kPa is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

<h3>What is Henry's law?</h3>

Mathematically, we can get this from Henry's law

From Henry law;

Concentration = Henry constant × partial pressure

Thus Henry constant = \frac{Concentration}{partial \;pressure}

Henry constant = \frac{4.32 \;X \;10^{-4} mol}{92.4kPa}

= 0.0467 X 10^{-4} M/kPa

Hence, 0.0467 X 10^{-4} M/kPa is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

Learn more about the Henry's law here:

brainly.com/question/16222358

#SPJ1

6 0
1 year ago
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