Help me please please

Mathematics

1 answer:

Tresset [83]2 years ago

4 0

Answer:

hope its help u

Step-by-step explanation:

$let \: the \: angle \: be \: \alpha \\ \tan( \alpha ) = \frac{p}{b} \\ \tan(32) = \frac{25}{x} \\ 0.62486= \frac{25}{x } \\ x = \frac{25}{0.62486} \\ x = 40$

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Romashka [77]

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8 0

2 years ago

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Which formula gives the x-coordinates of the maximum values for y = cos(x)?

solong [7]

We have been given a function $y=\cos(x)$ . We are asked to find the formula which gives the x-coordinates of the maximum values for given function.

We know that cosine function oscillates between $-1$ and 1 that is minimum value of cosine is $-1$ and maximum value is $1$ .

We also know that $\cos(0)=1$ and after period of cosine is $2\pi$ . This means after every $2\pi$ , we will get to $1$ .

So maximum of cosine is $2\pi n$ , where n is an integer.

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3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$