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Elina [12.6K]
2 years ago
10

Help me please please

Mathematics
1 answer:
Tresset [83]2 years ago
4 0

Answer:

hope its help u

Step-by-step explanation:

let \: the \: angle \: be \:  \alpha  \\  \tan( \alpha )  =  \frac{p}{b}  \\  \tan(32)  =  \frac{25}{x}  \\ 0.62486=  \frac{25}{x }  \\ x =  \frac{25}{0.62486}  \\ x = 40

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Figure ABCDE has vertices A(−2, 3), B(2, 3), C(5, −2), D(0, −4), and E(−2, −2). Plot the points on your own coordinate grid and
Anastasy [175]

There's a right angle that they want you to make a rectangle out of.  I'm ignoring that and using each of the five sides to make a triangle with the origin.

A.  Five triangles, zero rectangles.

B.

AB=4, the difference of the x coordinates since the y coordinates are the same

AE = 5, the difference in the y coordinates since the x coordinates are the same

C.  We'll use the Shoelace Formula, adding up all those triangles I made.  A triangle with vertices (0,0), (a,b), (c,d) has signed area A = (1/2)(ad-bc).  We go around counterclockwise so they all have positive areas, starting with AE, then ED, DC, CB, BA.

Area = (1/2) (  (-2)(-2) - 3(-2)  +  (-2)(-4) - (-2)(0)  +  0(-2) - (-4)(5)  + 5(3) - (-2)(2) + 2(3) - (3)(-2))

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3 years ago
A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia
Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which <em>k</em> items can be selected from <em>n</em> different items without replacement and  irrespective of the order.

{n\choose k}=\frac{n!}{k!(n-k)!}

Permutation is a mathematical procedure to determine the number of arrangements of <em>k</em> items from <em>n</em> different items respective of the order of arrangement.

^{n}P_{k}=\frac{n!}{(n-k)!}

In this case we need to select two different cards from a pack of 52 cards.

  • Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{52\choose 2}=\frac{52!}{2!(52-2)!}

      =\frac{52\times 51\times 50!}{2!\times50!}\\=1326

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

  • Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

^{n}P_{k}=\frac{n!}{(n-k)!}

^{52}P_{2}=\frac{52!}{(52-2)!}

       =\frac{52\times 51\times 52!}{50!}

       =52\times 51\\=2652

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

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