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strojnjashka [21]
4 years ago
6

Karens batting average was 0.444. She was at bat 45 times. How many hitd did she get?

Mathematics
1 answer:
Igoryamba4 years ago
7 0
Average of 0,444 in 45 battings can be wirtten as:

45 * 44,4% = 19,98

After rounding it up it'll give us 20 and that's exactly how many hits Karen got.
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Harman [31]
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2 years ago
Find the terminal point on the unit circle determined by 11pi/6 radiants
irga5000 [103]

Answer:

(\frac{\sqrt{3}}{2},-\frac{1}{2})

Step-by-step explanation:

The unit circle has the parametric equation:

x=\cos \theta

y=\sin \theta

where \theta=\frac{11\pi }{6} in our case is the terminal side of the angle in standard position.

We substitute to get:

x=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}

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\therefore (\frac{\sqrt{3}}{2},-\frac{1}{2}) is the required point.

6 0
3 years ago
Average Inventory The Yasuko Okada Fragrance Company (YOFC) receives a shipment of 400 cases of specialty perfume early Monday m
Ksenya-84 [330]

Answer:

Step-by-step explanation:

At the end of any given business day, CFFC has 400-80t cases of perfume on hand, where t = 1 represents Monday, t = 2 represents Tuesday and so on. The inventory becomes nil on Friday evening. So,

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a = 0

b = 5

Using the formular for average value, we have the average value as

\frac{1}{5-0}\int\limits^5_0 {(400-80t)}dt\\\\=\frac{1}{5}(400t-\frac{80t^2}{2})\limits^5_0\\\\=\frac{1}{5}(400t-40t^2)\limits^5_0\\\\=\frac{1}{5}(2000-1000)\\\\=200

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8 0
3 years ago
Suppose taxi fare from Logan Airport to downtown Boston is known to be normally distributed with a standard deviation of $2.50.
Mariulka [41]

Answer:

95% Confidence interval for taxi fare:  ($20.5,$24.2)

Step-by-step explanation:

We are given the following data set: for fares:

$22.10, $23.25, $21.35, $24.50, $21.90, $20.75, and $22.65

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{156.5}{7} = 22.35

95% Confidence interval:

\bar{x} \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

22.35 \pm 1.96(\frac{2.5}{\sqrt{7}} ) = 22.35 \pm 1.85 = (20.5,24.2)

6 0
3 years ago
Alex is 5 feet 6 inches tall. There are 2.54 centimeters in 1 inch. What is Alex’s height in centimeters?
Anna35 [415]
Im not sure about the second one, but for the first one, Alex’s height is 167.64 cm. :)
7 0
3 years ago
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