Answer: For this homework question, you’ll need to look up the molar mass of AgNO₃. Use this to calculate the number of moles in the sample.
Then note that silver is (quite usually) univalent, so there will be as many moles of AgCl as there were of AgNO₃.
Ask your instructor or tutor for more in-depth training, if need be. Good luck!
Explanation:
Answer:
35.42g
Explanation:
LiOH + KCI → LiCl + KOH
Let us determine the molar mass of LiOH and LiCl. This is illustrated below:
Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol
Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.
Now, we can obtain the theoretical yield of LiCl as follow:
From the equation above,
24g of LiOH reacted to produce 42.5g of LiCl.
Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.
From the above calculations, the theoretical yield of LiCl is 35.42g