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jolli1 [7]
3 years ago
11

Plutonium-240 decays according to the function \[Q(t)=Q _{o}e ^{-kt}\] where Q represents the quantity remaining after t years a

nd k is the decay constant, 0.00011.. How long will it take 36 grams of plutonium-240 to decay to 12 grams?. A. 18,900 years. B. 1.44 years. C. 9,990 years. D. 2,100 years.
Chemistry
2 answers:
enyata [817]3 years ago
8 0
<span>C. 9,990 years is the correct answer

</span>
marishachu [46]3 years ago
4 0
To answer the question above, substitute the given values to the given equation,
                                   Q(t) = Q x e^-kt
  
                          12 grams = (36 grams) x e^(-0.00011)(t)

Solving for t gives t = 9,987.38 years or approximately equal to 9,990 years. Thus, the answer is letter C.












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If 10 staples have a mass of 1.33 g, what will be the mass of 225 staples?
Leona [35]

Answer:

A) 29.9g

Explanation:

first find the weight of 1 staple.

then multiply with 225

5 0
3 years ago
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The image shows the representation of an unknown element in the periodic table. A square is shown. Inside the square twelve is w
avanturin [10]

Answer:

The combined mass of all the protons and electrons is 24.305.

Explanation:

From the information given about the atom, we can see that the relative atom mass of the element is 24.305.

The relative atomic mass of an atom is the combined mass of all its isotope in proportion of their geonormal abundances. On the periodic table, this mass deals with the amount of protons and neutrons present in a given atom.

7 0
3 years ago
In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2
allsm [11]

Answer:

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

Explanation:

SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

Balance the charge by adding 2 electrons on product side:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-....[1]

Reduction :

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)

Balance O by adding water on required side:

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

Now, balance H by adding H^+ on the required side:

SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

At last balance the charge by adding electrons on the side where positive charge is more:

SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)..[2]

Adding [1] and [2]:

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

4 0
3 years ago
3 &amp; 4 Help pleaseeeee
kvasek [131]
3 is C i believe, and as for 4 minerals are solid, natural.. that's about all I can say...
4 0
3 years ago
The density of gold is 19.3 g /cm cubed The density of iron pyrite is 5.0 g /cm cubed. Is a nugget of iron pyrite and a nugget o
telo118 [61]
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\rho = \frac{m}{V}\ \to\ V = \frac{m}{\rho}

The greater the density the lower the volume. This means, the volume of gold nugget will be smaller than the volume of iron pyrite nugget.

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6 0
3 years ago
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