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Why is a chemical equilibrium described as dynamic?

Mariulka [41]

Answer:

Chemical equilibrium is also called as dynamic equilibrium because it in chemical equilibrium, the equilibrium can shift towards both sides that is reactant and product known as equilibrium shifting. And in chemical equilibrium, the reaction is going on but the rate of formation of reaction is equals to the rate of formation of product.

Hope this helps!

8 0

3 years ago

Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb calorimeter has a

dexar [7]

Answer:

Its final temperature is 25.8 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)

When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.

In this case, you know:

Q= 14 kJ= 14,000 J

c= 3.55 $\frac{J}{g*C}$

m=1.20 kg= 1200 g (1 kg=1000 g)
Tfinal= ?
Tinitial= 22.5 °C

Replacing:

$14,000 J= 3.55 \frac{J}{g*C}*1200 g*(Tfinal-22.5C)$

Solving:

$\frac{14,000J}{3.55\frac{J}{g*C} *1200 g} =T final - 22.5C$

3.3=Tfinal - 22.5 C

3.3 + 22.5=Tfinal

Tfinal= 25.8 °C

Its final temperature is 25.8 °C

3 0

3 years ago

Read 2 more answers

Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a

svetoff [14.1K]

Answer:

See Explanation

Explanation:

For SF6;

Since;

1.25 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55

For SF4;

Since;

1.88 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/ 1.88 = 2.36

Hence;

Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4

=

3.55/2.36 = 1.5

Hence the law of multiple proportion is obeyed here.

3 0

3 years ago

A certain first-order reaction (A→products) has a rate constant of 8.10×10−3 s−1 at 45 ∘C. How many minutes does it take for the

stira [4]

Answer:

The answer is 5.7 minutes

Explanation:

A first-order reaction follow the law of $Ln [A] = -k.t + Ln [A]_{0}$ . Where [A] is the concentration of the reactant at any t time of the reaction, $[A]_{0}$ is the concentration of the reactant at the beginning of the reaction and k is the rate constant.

Dropping the concentration of the reactant to 6.25% means the concentration of A at the end of the reaction has to be $[A]=\frac{6.25}{100}.[A]_{0}$ . And the rate constant (k) is 8.10×10−3 s−1