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deff fn [24]
3 years ago
7

Please helpppp

Chemistry
1 answer:
AysviL [449]3 years ago
4 0

Answer:

3

Explanation:

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According to Sam's soap recipe, she needs 855
AURORKA [14]

Answer:

gwbwhsusjhsbdsbdiddushsbdbdjsisshbwwiwjwbssidhdbdhdjdidjdbsbd

7 0
3 years ago
What is the mass of 0.60 moles of Al
KIM [24]

16 g. The mass of 0.60 mol Al is 16 g.

Molar mass of Al = 26.98 g/mol

Mass of Al = 0.60 mol Al x (26.98 g Al/1 mol Al) = 16 g Al

6 0
3 years ago
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Please help! Asap! :)
timama [110]

The first one is true.

The second one is false.

4 0
3 years ago
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C2H6(g) + O2(g) → CO2(g) + H2O(g)
attashe74 [19]

Answer:

2C2H6 + 7O2 --> 4CO2 + 6H20

Explanation:

Balanced equation

5 0
3 years ago
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Consider the reaction CH4(g) 2O2(g)CO2(g) 2H2O(g) Using standard thermodynamic data at 298K, calculate the entropy change for th
zvonat [6]

Answer:

the entropy change for the surroundings when 1.62 moles of CH4(g) react at standard conditions is −8.343 J/K

Explanation:

The balanced chemical equation of the reaction in the question given is:

CH_{4(g)}  + 2O_{2(g)} \to CO_{2(g)} + 2 H_2O _{(g)}

Using standard thermodynamic data at 298K.

The entropy of each compound above are listed as follows in a respective order.

Entropy of (CH4(g)) = 186.264 J/mol.K

Entropy of (O2(g)) = 205.138 J/mol.K

Entropy of (CO2(g)) = 213.74 J/mol.K

Entropy of (H2O(g)) = 188.825 J/mol.K

The change in Entropy (S) of the reaction is therefore calculated as follows:

=1*S(CO2(g)) + 2*S(H2O(g)) - 1*S( CH4(g)) - 2*S(O2(g))

=1*(213.74) + 2*(188.825) - 1*(186.264) - 2*(205.138)

=  -5.15  J/mol.K

Given that :

the number of moles = 1.62 of CH4(g) react at standard conditions.

Then;

The change in entropy of the rxn = 1.62 \ mol * -5.15 \  J/mol.K

= −8.343 J/K

6 0
3 years ago
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