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2 years ago

What volume of o2 is needed to react fully with 720. Ml of nh3

1 answer:

6 0

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

$\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O$

From the stoichiometry of the reaction, it can be said that,

$(4 \times 22.4)$ L of ammonia reacts with $(5 \times 22.4)$ L of oxygen gas.

So, 0.720 L of ammonia will react with:

$\dfrac{ (5 \times 22.4)}{(4 \times 22.4)} \times 0.720 = 0.9 \;\rm L$

Therefore, the volume of oxygen required is 900 mL.

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A ball sits on top of a hill. The wind blows and the ball begins rolling down the hill. What caused the ball to start moving?

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3 years ago

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2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?

Sophie [7]

<h3>Answer:</h3>

$\displaystyle 0.5 \ mol \ CO_2$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles
Compounds

<u>Stoichiometry</u>

Using Dimensional Analysis
Analyzing Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

[DA] Set up: $\displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.5 \ mol \ CO_2$

7 0

2 years ago

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

$Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}$

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

$\frac{164}{120}$

100 grams of NaOH is produced from =

$\frac{164}{120}\times100$ gram of Na3PO4

calculate,

= 136.67 g

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3 years ago

Now that we have put a coefficient of 3 in front of caso4, what coefficient should go in front of cacl2 to balance calcium (ca)?

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What is the relationship between nucleic acids and nucleotides?

maw [93]

The nucleotides are monomers of nucleic acid.

The nucleic acids are the macro molecules. They are two types- DNA and RNA. The nucleic acid, DNA consists of nucleotide which are monomers of the DNA. The nucleotides have three components such as pentose sugar, nitrogen bases, and phosphate.

They are the backbone of DNA. DNA is the polymer of nucleotide, and this DNA is coming under nucleic acids. The nucleotides form DNA, and DNA forms the nucleic acid. They are interlinked with each other.

Nucleic acids are the center for storing all the information. The deoxyribose nucleic acid or DNA is the center for storing all the genetic information.

The genetic material is inherited from the parents to the children. The characters are transferred from one generation to another.

The characters such as hair color, hair type, eye color are some of the genetic information that is carried from one generation to another via nucleic acids.

Nucleotide is the basic unit of nucleic acid (DNA and RNA) which store the genetic code of the cell.

It consists of sugar base (ribose or deoxyribose), nitrogenous base (A, T, G, C and U), and phosphate group.

Nucleotides (specially ATP) provides the energy for most of the cellular processes.

Therefore, with the above statements we got to know that both nucleic acid and nucleotides are genetically modified.

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1 year ago