Hey mate here is your answer.
➛ 6(x-2) = 4(x+3)
➛ 6x-12 = 4x + 12
➛ 6x - 4x = 12 + 12
➛ 2x = 24
➛ x = ![\frac{24}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%3C%2Fstrong%3E%3Cstrong%3E24%3C%2Fstrong%3E%3Cstrong%3E%7D%7B%3C%2Fstrong%3E%3Cstrong%3E2%3C%2Fstrong%3E%3Cstrong%3E%7D%20)
⛬ x = 12
For determining the correct degree of a polynomial, you need to look at each term and find the degree by adding the exponents of each variable in it. The largest degree is the degree of the polynomial.
7x^6 has largest degree of the given polynomial, so your answer is D.6
Answer:
<h2>1. t=2m</h2>
Rewrite the equation as 2m=t.
2m=t
Divide each term by 2 and simplify.
m=t/2
<h2>2. y=2x+1</h2>
Isolate the variable by dividing each side by factors that don't contain the variable.
x=y/2−1/2
Step-by-step explanation:
Hope it is helpful....
vertex form wow tht's advance um i'll say what you wrote up there is the answer
Answer:
![x=1.16](https://tex.z-dn.net/?f=x%3D1.16)
Step-by-step explanation:
we have
![4(e^x)=12.76](https://tex.z-dn.net/?f=4%28e%5Ex%29%3D12.76)
Solve for x
That means ---> Isolate the variable x
Divide by 4 both sides
![(e^x)=3.19](https://tex.z-dn.net/?f=%28e%5Ex%29%3D3.19)
Apply ln both sides
![ln[(e^x)]=ln(3.19)](https://tex.z-dn.net/?f=ln%5B%28e%5Ex%29%5D%3Dln%283.19%29)
Apply property of logarithms (power rule) left side
![(x)ln(e)=ln(3.19)](https://tex.z-dn.net/?f=%28x%29ln%28e%29%3Dln%283.19%29)
Remember that
![ln(e)=1](https://tex.z-dn.net/?f=ln%28e%29%3D1)
![x=ln(3.19)](https://tex.z-dn.net/?f=x%3Dln%283.19%29)
![x=1.16](https://tex.z-dn.net/?f=x%3D1.16)