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Gekata [30.6K]
3 years ago
8

In the reaction 2co ( g) + o2( g) → 2co2( g), what is the ratio of moles of oxygen used to moles of co2produced?

Chemistry
1 answer:
KIM [24]3 years ago
8 0
In the reaction 2co ( g) + o2( g) → 2co2( g), the ratio of moles of oxygen used to moles of co2produced is 1:2.
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Answer:

Physical and psychological dependence is high, and withdrawal symptoms include watery eyes, runny nose, loss of appetite, irritability, tremors, panic, abdominal cramps and diarrhea, nausea, chills, and sweating. Use of contaminated syringes/needles to inject drugs may result in serious blood borne infections such as HIV-AIDS and hepatitis.

6 0
3 years ago
The arrows in the chart below represent phase transitions. Three bars are shown labeled Solid, Liquid, and Gas. They are connect
tester [92]

Answer:

1,2,3

Explanation:

Heat gain implies that heat is absorbed by the system in order to make the stated phase transition possible.

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Also, transition from solid to liquid requires energy to break intermolecular bonds.

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4 0
3 years ago
Read 2 more answers
Does anyone know the answers for these
Alexeev081 [22]

Answer: 1. 0.045moles

2.  2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

1. \text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles

2. Mass of C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g

4 0
2 years ago
8)<br> As the skydiver falls to Earth, she experiences positive acceleration due to
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Answer:

Excitement.

Explanation:

7 0
2 years ago
. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temp
marin [14]

Answer:

The answer to your question is Pressure = 5 atm

Explanation:

Data

Volume 1 = V1 = 0.5 l

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

                      V1P1 = V2P2

Solve for P2

                     P2 = V1P1/V2

Substitution

                     P2 = (0.5 x 1) / 0.1

Simplification

                     P2 = 0.5/0.1

Result

                     P2 = 5 atm          

3 0
3 years ago
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