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2 years ago

What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?

Chemistry

1 answer:

Lerok [7]2 years ago

4 0

Answer:

2.68 Liters

Explanation:

ideal gas law

PV=NRT

to get the volume

rearrange the formula

V=nRT/P

R molar gas constant is in units joules per mole kelvin :

8.314 J/(mol K) (joules per mole kelvin)

T temperature part of this is in kelvin so you have to convert the Celsius temperature to kelvin

1 Celsius is 274.15 kelvin so

83.4 Celsius is 356.55 kelvin

P pressure is in Pascal or Pa units

so you have to convert atm into Pa

1 atm is 201636.8 Pa or Pascals so

1.99 atm is 201636.8 Pa

V volume will be in cubic meters or m^3

m^3 will need to changed to liters

1 cubic meter or m^3 is 1000 liters

n amount of substance is in moles

again the rearranged formula is

V=nRT/P

(0.182*8.314*356.55)/201636.8 =

0.00267566693 cubic meters or m^3

1 cubic meter or m^3 is 1000 liters so

0.00267566693 cubic meters or m^3 times 1000 =

2.67566693 liters

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Answer:

the answer is 90g

Explanation:

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3 years ago

What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm

Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

Difference in mass = 985.32 - 984.5 = 0.82 g

Explanation:

Part I :

$n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}$

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = $5\times 196.96$ g

4.99 moles of gold contain = 984.8 g

Mass of ${3.01\times 10^{24}}$ atoms of gold = 984.5 g

Part II :

Density of Gold = $19.32 g/cm^{3}$

Volume of the cuboid = $length\times breadth\times height$

Volume of the gold bar = $6.00\times 4.25\times 2.00$

Volume of the gold bar = 51 $cm^{3}$

Using formula,

$Density = \frac{mass}{Volume}$

$Mass = Density\times Volume$

$Mass = 19.32 \times 51$

Mass = 985.32 g

So, A gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of 985.32 g

Difference in mass = 985.32 - 984.5 = 0.82 g

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3 years ago

.) Neon and HF have approximately the same molecular masses. a.)Explain why the boiling points of Neon and HF differ b.)Compare

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Answer:

See explanation

Explanation:

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2 years ago