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julsineya [31]
2 years ago
12

What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?

Chemistry
1 answer:
Lerok [7]2 years ago
4 0

Answer:

2.68 Liters

Explanation:

ideal gas law

PV=NRT

to get the volume

rearrange the formula

V=nRT/P

R molar gas constant is in units joules per mole kelvin :

8.314 J/(mol K) (joules per mole kelvin)

T temperature part of this is in kelvin so you have to convert the Celsius temperature to kelvin

1 Celsius is 274.15 kelvin so

83.4 Celsius is 356.55 kelvin

P pressure is in Pascal or Pa units

so you have to convert atm into Pa

1 atm is 201636.8 Pa or Pascals so

1.99 atm is 201636.8 Pa

V volume will be in cubic meters or m^3

m^3 will need to changed to liters

1 cubic meter or m^3 is 1000 liters

n amount of substance is in moles

again the rearranged formula is

V=nRT/P

(0.182*8.314*356.55)/201636.8 =

0.00267566693 cubic meters or m^3

1 cubic meter or m^3 is 1000 liters so

0.00267566693 cubic meters or m^3 times 1000 =

2.67566693 liters

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We are given:

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Putting values in above equation, we get:

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Boyle's law is expressed mathematically as:

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Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

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In this case, you know:

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