All categories

3 years ago

How does fluorine react with ethene?

Chemistry

2 answers:

Nostrana [21]3 years ago

4 0

By breaking a carbon double bond and adding fluorine. Answer: 2

Viefleur [7K]3 years ago

4 0

Option 3: By removing hydrogen because of fluorine's attraction to hydrogen's nucleus.

The reaction of ethene and halogen generally breaks the carbon-carbon double bond and substitution of halogen on carbon takes place, this is known as halogenation reaction. This is in the case of reaction of ethene with chlorine, bromine and iodine. In the case of fluorine, due to high electronegativity it get attracts to the nucleus of hydrogen and form hydrogen fluorine gas. Therefore, halogentaion reaction do not take place in the case of ethene and iodine.

Ethene explosively reacts with fluorine to form carbon and hydrogen fluoride gas. The reaction is as follows:

$CH_{2}CH_{2}+2F_{2}\rightarrow 2C+4HF$

You might be interested in

Which of the following elements has the greatest atomic radius?<br> Al<br> S<br> Si<br> C

suter [353]

Answer:

The answer to your question is: Al, Si have the greatest and S, C have the smallest.

Explanation:

Atomic radius increases from right to left in the periodic table.

Atomic radius increases from the upper section to the lower section of the periodic table.

Order of the atomic radius from highest to lowest.

Al, Si, S and C

6 0

3 years ago

There are two physical properties of minerals that both result in smooth, flat surfaces with specific angles between them. The f

stich3 [128]

Answer:

3. crystal habit and cleavage.

Explanation:

Crystal habit is a distinctive characteristic which is shown in its general shape, crystallographic forms, how developed each form is.

Cleavage is the ability of a mineral to break in smooth planes parallel to zones of weak bonding. Cleavage in three directions at right angles (90o). Cubic cleavage. Cleavage in three directions not at right angles (120o and 60o).

3 0

3 years ago

Write the balanced NET IONIC equation for the reaction that occurs when perchloric acid and calcium hypochlorite are combined. I

Elanso [62]

Answer:

$H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}$

Explanation:

Hello there!

In this case, since perchloric acid is HClO4 and is a strong acid and calcium hypochlorite is Ca(ClO)2, the undergoing molecular chemical reaction turns out:

$2HClO_4{(aq)}+Ca(ClO)_2{(aq)}\rightarrow 2HClO{(aq)}+Ca(ClO_4)_2{(aq)}$

Thus, since the resulting hypochlorous acid is weak, it does not fully ionize, so it remains unionized, however, we can write the ions for the other species:

$2H^++2(ClO_4)^-+Ca^{2+}+2(ClO)^-\rightarrow 2HClO{(aq)}+Ca^{2+}+2(ClO_4)^-$

Now, we can cancel out the spectator ions, calcium and perchlorate, to obtain:

$2H^+(aq)+2(ClO)^-(aq)\rightarrow 2HClO{(aq)}\\\\H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}$

Best regards!

3 0

3 years ago

An electron in a hydrogen atom relaxes to the n=4 level, emitting light of 74 THz.

Solnce55 [7]

Delta E = Ef - Ei
E = energy , h = plank constant , v = frequency
h= 6.626 * 10 ^-34 j*s , T = 10 ^ 12 , v = 74 * 10 ^12 Hz , Hz = s^-1

E = ( 6.626 * 10^ -34 j*s) ( 74 * 10 ^ 12 s^ -1 ) = 4.90 * 10 ^ -20 J
Delta E = Ef - Ei
-4.90 * 10 ^ -20 J = -2.18 * 10 ^ -18J ( 1/4 ^2 - 1/x ^2)
0.0225 = 0.0625 - ( 1/x ^ 2)
0.225 - 0.0625 = - 1/ x ^ 2

- 0.0400 = - 1/x ^2 = -1 / - 0.0400 = x^2
25 = x^2
x = 5

6 0

3 years ago

Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.Drag the appropriate items to their respective b

Sonja [21]

Answer:

Ag+(aq)+Br−(aq)→AgBr(s) NEGATIVE

CaCO3(s)→CaO(s)+CO2(g)2 POSITIVE

NH3(g)→N2(g)+3H2(g) POSITIVE

2Na(s)+Cl2(g)→2NaCl(s) NEGATIVE

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g) POSITIVE

I2(s)→I2(g) POSITIVE

Explanation:

We have to remember, to solve this problem, that the entropy of a gas is higher than that of a liquid which in turn is higher than the solid. Therefore, comparing the reactants and products look for changes in the state of reactants and products. We also have to look for the increase or decrease of moles of each state based on the balanced chemical reaction.

Ag+(aq)+Br−(aq)→AgBr(s)

The reaction product is a single solid and the the reactants were 2 species in solution. The change in entropy is negative.

CaCO3(s)→CaO(s)+CO2(g)2

Here we have a solid reactant and we have a solid product plus a gas product. The change in entropy is positive.

NH3(g)→N2(g)+3H2(g)

We have 4 mole gases as products starting from 1 mol reactant gas, the entropy has increased.

2Na(s)+Cl2(g)→2NaCl(s)

In this reaction 2 mol solid Na and 1 mol Cl₂ gas are converted into 2 mol solid NaCl, the entropy has decreased.

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g)

The products are 7 mol of gas versus 6 mol of gas reactants and therefore entropy has increased.

I2(s)→I2(g)

1 mol solid I₂ goes into 1 mol gas making the change in the entropy higher.

4 0

3 years ago