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gogolik [260]
3 years ago
11

The chemical formula for magnesium oxide is MgO. A chemist determined by measurements that 0.030 moles of magnesium oxide partic

ipate in a chemical reaction. Calculate the mass of magnesium oxide that participates.
Chemistry
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer:

1.209g of MgO participates

Explanation:

In this problem, we have 0.030 moles of MgO that participates in a particular reaction.

And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.

To convert moles to grams we need to use molar mass of the compound:

<em>1 atom of Mg has a molar mass of 24.3g/mol</em>

<em>1 atom of O has a molar mass of 16g/mol</em>

<em />

That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol

And mass of 0.030 moles of MgO is:

0.030 moles MgO * (40.3g/mol) =

<h3>1.209g of MgO participates</h3>
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Answer:

stratosphere

Explanation:

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3 years ago
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What is the mass of 7.50 moles of magnesium chloride, mgcl2?
Natali5045456 [20]
MgCl2 = 1Mg + 2Cl = 1(24.3) + 2(35.45) = 95.2g/1mole
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8 0
4 years ago
A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is
Charra [1.4K]

Answer:

[H^{+}] = 0.761 \frac{mol}{L}

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

pH = 0.119

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L)  \\ n_{H^{+} } from HNO_{3}  = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

n_{H^{+} } from HCl = (5.00)(0.093)

n_{H^{+} } from HCl = 0.465 mol

n_{H^{+} } from HNO_{3}  = (8.00)(0.037)

n_{H^{+} } from HNO_{3}  = 0.296 mol

n_{H^{+}(total) } = 0.296 + 0.465

n_{H^{+}(total) } = 0.761 mol

For molar concentration of hydrogen ions:

[H^{+}]  = \frac{n_{H^{+}}(mol)}{V(L)}

[H^{+}] = \frac{0.761}{1.00}

[H^{+}] = 0.761 \frac{mol}{L}

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

K_{w} = [H^{+} ][OH^{-} ]

[OH^{-}]=\frac{Kw}{[H^{+}] }

[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

The pH of the solution can be measured by the following formula:

pH = -log[H^{+} ]

pH = -log(0.761)

pH = 0.119

5 0
3 years ago
In the balanced reaction below, what is the mole ratio comparing iron (Fe) and oxygen gas (O2)?
zepelin [54]

The given balanced reaction is,

4Fe(s) + 3O_{2}(g) --->2Fe_{2}O_{3} (s)

The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

\frac{Fe}{O_{2}} = \frac{4 mol Fe}{3 mol O_{2}}

\frac{Fe}{Fe_{2}O_{3}} = \frac{4 mol Fe}{2 Fe_{2}O_{3}}

\frac{O_{2}}{Fe_{2}O_{3}} =\frac{3 mol O_{2}}{2molFe_{2}O_{3}}

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Draw the condensed structural formulas for all the possible haloalkane isomers that have four carbon atoms and a bromine.
meriva

<u>Answer:</u> The isomers are shown in the image below.

<u>Explanation:</u>

Isomers are defined as the chemical compounds having the same number and kinds of atoms but arrangement are different.

For the alkane having four carbon atoms and 1 bromine atom, the IUPAC name of the haloalkane is bromobutane

There are 4 possible isomers for the given haloalkane compound:

  1. 1-bromobutane
  2. 2-bromobutane
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The isomers of the given organic compound is shown in the image below.

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