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gogolik [260]
2 years ago
11

The chemical formula for magnesium oxide is MgO. A chemist determined by measurements that 0.030 moles of magnesium oxide partic

ipate in a chemical reaction. Calculate the mass of magnesium oxide that participates.
Chemistry
1 answer:
tamaranim1 [39]2 years ago
3 0

Answer:

1.209g of MgO participates

Explanation:

In this problem, we have 0.030 moles of MgO that participates in a particular reaction.

And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.

To convert moles to grams we need to use molar mass of the compound:

<em>1 atom of Mg has a molar mass of 24.3g/mol</em>

<em>1 atom of O has a molar mass of 16g/mol</em>

<em />

That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol

And mass of 0.030 moles of MgO is:

0.030 moles MgO * (40.3g/mol) =

<h3>1.209g of MgO participates</h3>
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How many grams of NaOH are produced from 20.0 grams of Na2CO3?
natita [175]

Answer:

Hope this helps!

Explanation:

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams

4 0
2 years ago
1. ¿Cuál de los factores se deben emplear para convertir: a. ¿Número de moles de cloro en número de moles de NaCl? b. Moles de s
Alex

Answer:

Número de moles de cloro en número de moles de NaCl

Explanation:

espero que si sea la correcta

7 0
2 years ago
What would happen if I swallowed a mento then drank some coca cola?
Sholpan [36]
Your stomach will bubble lol it might kind of tickle
4 0
3 years ago
Read 2 more answers
Write the formulas of the following compounds:
dem82 [27]

Answer:

a) Li2CO3

b) NaCLO4

c) Ba(OH)2

d) (NH4)2CO3

e) H2SO4

f) Ca(CH3COO)2

g) Mg3(PO4)2

f) Na2SO3

Explanation:

a) 2Li + CO3 ↔ Li2CO3

b) NaOH * HCLO4 ↔ NaCLO4 + H2O

c) Ba + 2H2O ↔ Ba(OH)2 +

d)  2NH4 + H2CO3 ↔ (NH4)2CO3 + H2O

c) SO2 + NO2 +H2O ↔ H2SO4 + NOx

f) 2CH3COOH + CaO ↔ Ca(CH3COOH)2 + H2O

g) 3MgO + 2H3PO4 ↔ Mg3(PO4)2 + H2O

h) NaOH + H2SO3 ↔ Na2SO3 + H2O

6 0
3 years ago
If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is
kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

<u>Data:</u>

  • P₁ (initial pressure) = 500 torr
  • V₁ (initial volume) = 0.5 L
  • P₂ (final pressure) = 700 torr

<u>Wanted:</u>

  • V₂ (final volume)

<u>Equation:</u>

  • P₁V₁ = P₂V₂  →  V₂ = P₁V₁ / P₂

<u>Solution:</u>

  • V₂ = \frac{(500 torr)(0.5 L)}{700 torr} = 0.3571 L or 0.4 L
8 0
2 years ago
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