All categories

2 years ago

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics

1 answer:

Korvikt [17]2 years ago

4 0

Answer:

Second choice

Explanation:

I suppose ME is the same as POTENTIAL energy

ME = mgh = 70 * 10 * 12 = 8400j

Half way down, 4200 j is converted to Kinetic Energy

1/2 m v^2 = 4200

1/2 (70) v^2 = 4200 v = 10.95 m/s

Just before impact ALL of the 8400 j is now KE
1/2 (70)v^2 = 8400 v = 15.49 m/s

You might be interested in

Determine the energy, in electron volts, of an emitted photon when an electron transition from n=3 to n=2 occurs

tensa zangetsu [6.8K]

Give me some answer choices and i will be happy to help

7 0

3 years ago

28. Ken and Musa shared a cake such that Ken got twice the size

ratelena [41]

Answer:

$Musa = \frac{1}{3}$

$Ken = \frac{2}{3}$

Explanation:

Given

$Ken = 2 * Musa$ --- Ken's share

Required

The fraction each got

Since they both shared a cake, we have:

$Ken + Musa = 1$

Substitute: $Ken = 2 * Musa$

$2 * Musa+ Musa = 1$

Factorize

$Musa(2+ 1)= 1$

$Musa(3)= 1$

Divide both sides by 3

$Musa = \frac{1}{3}$

Recall that: $Ken = 2 * Musa$

$Ken = 2 * \frac{1}{3}$

$Ken = \frac{2}{3}$

3 0

2 years ago

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the shap

AURORKA [14]

Answer: The height of the pile increasing is increasing at $0.16\frac{ft}{min}$

Explanation:

Given

Rate at which gravel is being dumped , $\frac{\mathrm{d} V}{\mathrm{d} t}=10\frac{ft^{3}}{min}$

=>Rate of increase of volume of cone= $\frac{\mathrm{d} V}{\mathrm{d} t}=10\frac{ft^{3}}{min}$

If height of the cone at any instant is h then the diameter of cone is also h

Volume of cone , $V=\frac{\pi r^{2}h}{3}=\frac{\pi h^{3}}{4\times 3}=\frac{\pi h^{3}}{12}$

Now differentiate both sides w.r.t time(t)

$\frac{\mathrm{d} V}{\mathrm{d} t}=\frac{\pi h^{2}}{4}\frac{\mathrm{d} h}{\mathrm{d} t}$

Therefore at h = 9 ft

$10=\frac{\pi \times 9^{2}}{4}\times \frac{\mathrm{d} h}{\mathrm{d} t}$

=> $\frac{\mathrm{d} h}{\mathrm{d} t}=0.16\frac{ft}{min}$

Thus the height of the pile increasing is increasing at $0.16\frac{ft}{min}$

6 0

3 years ago

I can't find this answer anywhere, so I'll ask here: what item did they base the SI unit of mass (grams) off of? (in other words

nevsk [136]

The SI Unit of the gram was based off the weight of a 1 cm cube of water that was at a temperature of 4 degrees Celsius.

3 0

3 years ago

This painting represents the milky way galaxy as it might appear from a distance. Identify the indicated features.

aksik [14]

The indicated features of how the painting represents the milky way galaxy include the following:

Spiral arm

Bulge

Disk

<h3>What is Milky way?</h3>

This is the galaxy which comprises of our solar system and has a milky appearance when it's viewed from the earth.

The painting represented it as a result of the spiral arm and other features which are listed above.

Read more about Milky way here brainly.com/question/13956361

5 0

1 year ago