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Fudgin [204]
3 years ago
8

S waves are also known as

Physics
2 answers:
Nataly [62]3 years ago
7 0
<h3><u>Answer;</u></h3>

<em>S waves are known as secondary wave or shear waves</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Seismic wave are types of waves that result from break down of rocks within the earth or an explosion</u></em>. Seismic waves are classified as body waves and surface waves.
  • <em><u>Body waves are classified into either secondary waves or primary waves</u></em>. Commonly known as the<em><u> S-waves and the P-waves.</u></em>
  • <em><u>Secondary waves are types of body waves that move through an object's body unlike th</u></em>e case of surface waves. It is the second wave that is felt after an earthquake.

qaws [65]3 years ago
5 0
B. secondary waves aka shear waves          
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3 years ago
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
8_murik_8 [283]

Complete Question

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?

Answer:

\theta=274rev

Explanation:

From the question we are told that:

Angular velocity \omega=510rpm

Mass m=40.kg

Diameter d 75=>0.75m

Off Time t=40.0s

Oscillation at Power off N=210

Generally the equation for Angular displacement is mathematically given by

 \theta_{\infty}=\frac{w+w_0}{t}t

 w=\frac{2*\theta_{\infty}}{t}-w_0

 w=\frac{28210}{40*(\frac{1}{60})}-510

 w=120rpm

Generally the equation for Time to come to rest is mathematically given by

 t=(\frac{\omega_0}{\omega_0-\omega})t

 t=(\frac{510}{510-120rpm})(40.0)(\frac{1}{60})

 t=0.87min

Therefore Angular displacement is

 \theta =(\frac{120+510}{2})0.87

 \theta=274rev

6 0
3 years ago
2. A ladder 16cm long weighs 420N and it's centre of gravity is 7m from one end.It is carried horizontally by two boys,each hold
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Answer:

well the answers are 180 and 240 obviously

Explanation:

Download pdf
8 0
2 years ago
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Answer:

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Which of the following calculations is equal to 1?
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Answer:

we need to see the answers but probably 1 or -1

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3 years ago
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