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Fudgin [204]
3 years ago
8

S waves are also known as

Physics
2 answers:
Nataly [62]3 years ago
7 0
<h3><u>Answer;</u></h3>

<em>S waves are known as secondary wave or shear waves</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Seismic wave are types of waves that result from break down of rocks within the earth or an explosion</u></em>. Seismic waves are classified as body waves and surface waves.
  • <em><u>Body waves are classified into either secondary waves or primary waves</u></em>. Commonly known as the<em><u> S-waves and the P-waves.</u></em>
  • <em><u>Secondary waves are types of body waves that move through an object's body unlike th</u></em>e case of surface waves. It is the second wave that is felt after an earthquake.

qaws [65]3 years ago
5 0
B. secondary waves aka shear waves          
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A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the
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Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3  m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1       V = 1.50*10^-3  m^3       ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J

W = 3.12 J

Hope this helps!

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