To solve this problem it is necessary to apply the concepts related to the heat exchange of a body.
By definition heat exchange in terms of mass flow can be expressed as
Where
Specific heat
= Mass flow rate
= Change in Temperature
Our values are given as
Specific heat of air
From our equation we have that
Rearrange to find 
Replacing
Therefore the exit temperature of air is 53.98°C
Answer:
I think it's 23 ohms.
Explanation:
Not entirely sure about it.
hope this helps
Answer:
what do u mean.
Answer:
=4/5 because I'm not going to go back in a year meaning that they are you are
Explanation:
thermal expansion ∝L = (δL/δT)÷L ----(1)
δL = L∝L + δT ----(2)
we have δL = 12.5x10⁻⁶
length l = 200mm
δT = 115°c - 15°c = 100°c
putting these values into equation 1, we have
δL = 200*12.5X10⁻⁶x100
= 0.25 MM
L₂ = L + δ L
= 200 + 0.25
L₂ = 200.25mm
12.5X10⁻⁶ *115-15 * 20
= 0.025
20 +0.025
D₂ = 20.025
as this rod undergoes free expansion at 115°c, the stress on this rod would be = 0
