Answer:
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Explanation:
This type of form-fill can be described/developed based on the requirements or information needed by the organization in order to perfectly fulfill an order and also to retain customers by making the form very easy and interactive attached below is an example of such form fill interface
Answer:
Tmax = 2.934ksi
φ = 4.58°
Explanation:
Given.
Length = 100 ft
Maximum power = 2590 hp
Angular rotate = 1700 rpm .
Outer diameter of the shaft = 8 in. Wall thickness = 3/8 in.
Calculating angular velocity.
= 1700rev/min * 2πrad/rev * 1min/60s
= 56.67πrad/s
Convert power to ft.lb/s
2590hp = 2590 * 550
= 1424500ft.lb/s
At this point, we calculate torque.
Torque = Power/Angular Velocity
Torque = 1424500/56.67π
Torque = 8000.24lb.ft
Using the torsion formula, we'll calculate maximum stress due to the shear force acting on the body:
Tmax = ½(Tc/J)
Tmax =½ of (8001.24 * 12 * 4 )/ (π/4)(4⁴ - 3.625⁴)
Tmax = ½ * 5868.656298363693
Tmax = 2934.328149181846
Tmax = 2.934ksi
Calculating the angle twist
φ = TL/JG
φ = (8001.24 * 12 * 100 * 12 )/( (π/4)(4⁴ - 3.625⁴)(4⁴ - 3.625⁴)(11)(10^6))
φ = 0.08002 rad -- convert to degrees
φ = 4.58° --- approximated
Answer:
<em>a. 3.33 MPa</em>
<em>b. 0.276 m^2</em>
<em></em>
Explanation:
The image is attached below.
The load = 40 kN = 40000 N
side length of wooden post L = 120 mm = 0.12 m
side width of the wooden post B = 100 mm = 0.1 m
Area of the beam = L x B = 0.12 x 0.1 = 0.012 m^2
a. <em>Maximum bearing stress of the concrete footing = load/area</em>
max. bearing stress = 40000/0.012 = 3.33 x
Pa = <em>3.33 MPa</em>
b. If the average bearing stress in the soil is 145 kPa = 145000 Pa
<em>size of the footing will be = load ÷ average bearing stress</em>
size of footing = 40000/145000 ≅<em> 0.276 m^2</em>