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kipiarov [429]
3 years ago
5

Welding and cutting done in confined spaces must

Engineering
2 answers:
Papessa [141]3 years ago
7 0
The answer is true i’m 99% sure
ELEN [110]3 years ago
4 0
The answer is true. Have a good day
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Detailed solution is given below

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Stefan Lano needs displays that will show the musical instrument inventory in his chain of music stores that caters to musicians
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attached below is an example of  the form

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3 years ago
The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that deliv
Debora [2.8K]

Answer:

Tmax = 2.934ksi

φ = 4.58°

Explanation:

Given.

Length = 100 ft

Maximum power = 2590 hp

Angular rotate = 1700 rpm .

Outer diameter of the shaft = 8 in. Wall thickness = 3/8 in.

Calculating angular velocity.

= 1700rev/min * 2πrad/rev * 1min/60s

= 56.67πrad/s

Convert power to ft.lb/s

2590hp = 2590 * 550

= 1424500ft.lb/s

At this point, we calculate torque.

Torque = Power/Angular Velocity

Torque = 1424500/56.67π

Torque = 8000.24lb.ft

Using the torsion formula, we'll calculate maximum stress due to the shear force acting on the body:

Tmax = ½(Tc/J)

Tmax =½ of (8001.24 * 12 * 4 )/ (π/4)(4⁴ - 3.625⁴)

Tmax = ½ * 5868.656298363693

Tmax = 2934.328149181846

Tmax = 2.934ksi

Calculating the angle twist

φ = TL/JG

φ = (8001.24 * 12 * 100 * 12 )/( (π/4)(4⁴ - 3.625⁴)(4⁴ - 3.625⁴)(11)(10^6))

φ = 0.08002 rad -- convert to degrees

φ = 4.58° --- approximated

8 0
3 years ago
A 40-kN axial load is applied to a short wooden post that is supported by a concrete footing resting on undisturbed soil. Determ
Alla [95]

Answer:

<em>a. 3.33 MPa</em>

<em>b. 0.276 m^2</em>

<em></em>

Explanation:

The image is attached below.

The load = 40 kN = 40000 N

side length of wooden post L = 120 mm = 0.12 m

side width of the wooden post B  = 100 mm = 0.1 m

Area of the beam = L x B = 0.12 x 0.1 = 0.012 m^2

a. <em>Maximum bearing stress of the concrete footing = load/area</em>

max. bearing stress = 40000/0.012 = 3.33 x 10^{6} Pa = <em>3.33 MPa</em>

b. If the average bearing stress in the soil is 145 kPa = 145000 Pa

<em>size of the footing will be =  load ÷ average bearing stress</em>

size of footing = 40000/145000 ≅<em> 0.276 m^2</em>

4 0
3 years ago
What is the name of the model/shape below?
yuradex [85]

Answer:

H

Explanation:

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