Answer:
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Explanation:
given data
angles φ = 43.1 degrees
angles λ = 47.9 degrees
shear stress = 20.7 MPa (3000 psi)
stress σ = 45 MPa (6500 psi)
solution
we have given shear stress so first we calculate here resolved shear stress that is express as
resolved shear stress = σ cosφ cosλ .................1
here σ is stress and φ and λ are angles given
so put here value we get
resolved shear stress = σ cosφ cosλ
resolved shear stress = 45 cos(43.1) cos(47.9)
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Answer:
Explanation:
Explanation given in the attached document.
Answer:
Correct sentence: (c) more.
Explanation:
Otto cycle:
An ideal Otto cycle models the behavior of an explosion engine. This cycle consists of six steps, as indicated in the figure. Prove that the performance of this cycle is given by the expression
η = 1 - (1/r^(ρ-1))
where r = VA / VB is the compression ratio equal to the ratio between the volume at the beginning of the compression cycle and at the end of it. ρ=1.4
Diesel cycle:
The ideal Diesel cycle is distinguished from the ideal Otto in the combustion phase, which in the Otto cycle is assumed at a constant volume and in the Diesel at constant pressure. Therefore the performance is different.
If we write the performance of a Diesel cycle in the form
:
η = 1 - (1/r^(ρ-1)) × ( (r^ρ)-1)/(ρ^(r-1)) )
we see that the efficiency of a Diesel cycle differs from that of an Otto cycle by the factor in parentheses. This factor is always greater than the unit, therefore, for the same compression reasons r
diesel performance is less than otto performance
\ eta_ \ mathrm {Diesel} <\ eta_ \ mathrm {Otto} \,
Answer:
f=5.81 Hz
Explanation:
Given that
m= 0.3 kg
K= 0.4 N/mm
K= 400 N/m
C= 3.28
We know that undamped natural frequency given as
Now by putting the values
ω = 36.51 rad/s
We know that
ω = 2 π f
36.51 = 2 x π x f
f=5.81 Hz
So the undamped natural frequency is 5.81 Hz.
Answer: Thats alright bro keep yo head up
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