Answer:
point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))
Explanation:
The distance formula is the difference of the x coordinates squared, plus the difference of the y coordinates squared, all square rooted. For the general case, it appears you simply need to change how you have written the code.
point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))
Note, by moving the 2 inside of the pow function, you have provided the second argument that it is requesting.
You were close with your initial attempt, you just had a parenthesis after x1 and y1 when you should not have.
Cheers.
Numerical weather prediction (NWP) uses mathematical models of the atmosphere and oceans to predict the weather based on current weather conditions. Though first attempted in the 1920s, it was not until the advent of computer simulation in the 1950s that numerical weather predictions produced realistic results. A number of global and regional forecast models are run in different countries worldwide, using current weather observations relayed from radiosondes, weather satellites and other observing systems as inputs.
Answer:
//Program was implemented using C++ Programming Language
// Comments are used for explanatory purpose
#include<iostream>
using namespace std;
unsigned int second_a(unsigned int n)
{
int r,sum=0,temp;
int first;
for(int i= 1; I<=n; i++)
{
first = n;
//Check if first digit is 3
// Remove last digit from number till only one digit is left
while(first >= 10)
{
first = first / 10;
}
if(first == 3) // if first digit is 3
{
//Check if n is palindrome
temp=n; // save the value of n in a temporary Variable
while(n>0)
{
r=n%10; //getting remainder
sum=(sum*10)+r;
n=n/10;
}
if(temp==sum)
cout<<n<<" is a palindrome";
else
cout<<n<<" is not a palindrome";
}
}
}
Explanation:
The above code segments is a functional program that checks if a number that starts with digit 3 is Palindromic or not.
The program was coded using C++ programming language.
The main method of the program is omitted.
Comments were used for explanatory purpose.
Answer:
. Heat transfer can be higher if themal efficiency is lower.
Explanation:
The heat transfer rate to the river water is calculated by this expression:
![\dot Q_{L} = \dot Q_{H} - \dot W](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BL%7D%20%3D%20%5Cdot%20Q_%7BH%7D%20-%20%5Cdot%20W)
![\dot Q_{L} = (\frac{1}{\eta_{th}}-1 )\cdot \dot W\\\dot Q_{L} = (\frac{1}{0.54}-1)\cdot (600 MW)\\\dot Q _{L} = 511.111 MW](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BL%7D%20%3D%20%28%5Cfrac%7B1%7D%7B%5Ceta_%7Bth%7D%7D-1%20%29%5Ccdot%20%5Cdot%20W%5C%5C%5Cdot%20Q_%7BL%7D%20%3D%20%28%5Cfrac%7B1%7D%7B0.54%7D-1%29%5Ccdot%20%28600%20MW%29%5C%5C%5Cdot%20Q%20_%7BL%7D%20%3D%20511.111%20MW)
The actual heat transfer can be higher if the steam power plant reports an thermal efficiency lower than expected.
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