A.hydrophobic tail B.hyrophobic head C.sodium-potassium pump D.ATP
1 answer:
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Answer:
Null Hypothesis -
The observed frequency is approximately equal to the expected frequency of phenotype.
Explanation:
Pure Breeding Cross - TTww x ttWW
Genotype of offspring in F2 generation - TtWw
Null Hypothesis -
The observed frequency is approximately equal to the expected frequency of phenotype.
The chi square analysis is attached
The degree of freedom for this question is 3
The p value for X^2 estimated through chi square test is 0.5
Hence the null hypothesis is accepted.
