Question

Helium decays to form lithium. 6 2 he → 6 3 li 0 -1 e this type of nuclear decay is called .

Answer 1

To understand this question, we need some knowledge on radioactive decay. This type of nuclear decay is called a beta decay

Beta Decay

This is the process where a radioactive material is fired or naturally emits a beta particle which is equivalent to the lose of an electron and spontaneously becomes an entirely different element.

$^6_2He \to ^6_3 Li + ^0_-_1e$

The participating actors in this nuclear reaction are

• helium
• lithium
• electron

This is the decay process of helium particle in which it became a lithium particle and emitted an electron in the process.

Learn more on beta decay here;

brainly.com/question/9615302

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