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Amiraneli [1.4K]
2 years ago
13

Helium decays to form lithium. 6 2 he → 6 3 li 0 -1 e this type of nuclear decay is called .

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
8 0

To understand this question, we need some knowledge on radioactive decay. This type of nuclear decay is called a beta decay

<h3>Beta Decay</h3>

This is the process where a radioactive material is fired or naturally emits a beta particle which is equivalent to the lose of an electron and spontaneously becomes an entirely different element.

^6_2He \to ^6_3 Li + ^0_-_1e

The participating actors in this nuclear reaction are

  • helium
  • lithium
  • electron

This is the decay process of helium particle in which it became a lithium particle and emitted an electron in the process.

Learn more on beta decay here;

brainly.com/question/9615302

#SPJ4

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ehidna [41]

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0.29m-0.29m+10= 0.35m-0.29m

10=0.06 m

Divide by 0.06 for 10 and 0.06

10/0.06= 0.06/0.06 m

m= 166.66666

Answer is m = 166.66666- the number 6 continues

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3 years ago
Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

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3 years ago
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ohaa [14]
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3 years ago
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In fig if x+y=w+z then prove that AOB is a line.​
frez [133]

Answer:

As Given, x+y=w+z

To Prove: AOB is a line or x+y=180

∘

(linear pair.)

According to the question,

x+y+w+z=360

∘

∣ Angles around a point.

(x+y)+(w+z)=360

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(x+y)+(x+y)=360

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∣ Given x+y=w+z

2(x+y)=360

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(x+y)=180

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Hence, x+y makes a linear pair.

Therefore, AOB is a straight line

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