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andrew11 [14]
2 years ago
11

Complete the square 4y^2+x+8y+1=0

Mathematics
1 answer:
sammy [17]2 years ago
4 0

Answer: Simple and best practice solution for 4y^2+8y+1=0 equation. ... Begin completing the square. ... Square it (1) and add it to both sides.

Step-by-step explanation: Complete the square for x2+2x x 2 + 2 x.

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3(2x - 5)+ 5(x - 6)=-1<br><br> Solve for x
scZoUnD [109]

Answer:

x= 4

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Type your response in the box.
zysi [14]

Step-by-step explanation:

<u>Pattern 1</u> :

Arithmetic Sequence

Common term = 4

<u>Pattern 2</u> :

Geometric Sequence

Common ratio = 2

7 0
3 years ago
a school is conducted a canned food drive. Their goal is to collected 500 cans of food. They have reached 6/8 of their goal. How
fiasKO [112]
500 * 6 / 8 = 375 cans.
8 0
3 years ago
When solving 5 (<br>25) - 7. What is the correct sequence of operations? (5 points)​
Nana76 [90]

You would multiply 5 by 25 (125) and then subtract 7 (118). Parentheses, exponents, multiply/divide, then add/subtract.

3 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
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