You would first make the fractions improper (making the numerator bigger then the denominator) in order to do that times the denominator with the whole number and add the numerator.
Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions
Answer:
when y=3,X=15
here X is five times the value of y
so now when y= 5 then the value of X will be 25
hope you understand......
Answer: A
Step-by-step explanation: -2 is your y-int and if you do your rise over run it’s -1/2
Let's call n the number of days Marika's been training for the race, and
the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so

On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:

It would be easier to write this continued addition as multiplication, in which case those same equations would look like

Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that
. In general, we can say that

Which is expressed by option B.
(Bonus: What piece of information from this question did we not need to use here?)