The best answer is C! Hope I helped :D
HALOGENS have 7 electrons in their final shell regardless if the total number of atoms. These 7 electrons would be shared between the 's' and 'p' orbital in the form
ns² np⁵ (the same as the question). Attached is a table that highlights the fact that halogens have the same form in terms of the valence electrons.
Explanation:
Meso compounds are optically inactive stereoisomers. Despite of having chiral carbon, they do not show optical activity because it has a plane of symmetry in its structure itself. It is superposable on its mirror image.
Aldo sugars on reaction which reducing agents such as , NaBH₄ reduces the carbonyl group in the sugar to alcohol and gives corresponding alditol.
<u>The D- aldohexose which on reduction gives a meso alditol are allose and galactose. </u>
<u>The structure is shown in the image below. Thus, in allitol and galactitol formed have internal plane of symmetry which makes the optically inactive.</u>
CO2 + H2O = H2CO3
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Your equation is already balanced, and the reaction type is: </span><em><u>synthesis.</u></em>
Depending on the testing process being used, it may affect the object by making it shape differently, scratch, it or sometimes do absolutely nothing. hope this helps:)