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2 years ago

. How many ethyl groups are in the molecule 3, 3-diethylpentane?

Chemistry

1 answer:

Mamont248 [21]2 years ago

6 0

Answer:

2 groups

Explanation:

The molecule 3, 3-diethylpentane has 2 ethyl groups because the prefix di- means that there are 2 homogeneous substituent groups present in the molecule.

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A buffer contains the weak acid HA and its conjugate base A-. the weak acid has a p Ka of 4.82 and the buffer has a pH of 4.25.

klasskru [66]

<span>I think the correct answer is A. A buffer is a substance that resists small change in the acidity of a solution when an acid or base is added to the solution. Usually, a buffer involves a weak acid or a weak alkali and one of its salt.</span>

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2 years ago

A patient gets 2.1 L of fluid over 19 hours through an IV. The drop factor is 20 gtt/mL.Calculate the drip rate in drops per min

Aleks [24]

<span>The rate of infusion is 2.1L/19h or 2100mL/19h (as 1L = 100 mL).

To convert 19 hours to minutes we multiply as follows:

19 hours = (19 hours) x (60 minutes/1 hour) = 1140 minutes

So the rate of infusion becomes:

2100mL /1140 min

In order to converted mL to drops (gtt) we multiply the rate of infusion with the drop factor to get the drip rate:

(2100mL/1140min) x (20 gtt/mL) = 36.8 gtt/min</span>

8 0

3 years ago

The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 H

neonofarm [45]

Answer:

25 coolers are need to be produce and sell in order to minimize the cost.

Explanation:

$C = 0.005x^2-0.25x+12$ ..[1]

Differentiating the given expression with respect to dx.

$\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}$

$\frac{dC}{dx}=0.01x-0.25+0$

Putting , $\frac{dC}{dx}=0$

$0=0.01x-0.25+0$

$0.01x=0.25$

x = 25

Taking second derivative of expression [1]

$\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01$

$\frac{d^2C}{dx^2}>0$ (minima)

25 coolers are need to be produce and sell in order to minimize the cost.

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3 years ago

For the reaction below, Kp = 1.59 at 100°C. If 1.0 g of SrCO3 is placed in an empty 5.00 L reactor and allowed to reach equilibr

Sergio [31]

Answer:

$p_{CO_2}^{eq}=1.59atm$

Explanation:

Hello, in this case, one could consider the undergoing chemical reaction as:

$SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)$

Thus, since 1.0 g of strontium carbonate is placed, the equilibrium equation takes the following form, excluding the solid-stated species and considering just the carbon dioxide as it is gaseous:

$Kp=p_{CO_2}^{eq}=1.59atm$

Hence, since at the beginning there is no carbon dioxide, its pressure at equilibrium equals Kp:

$Kp=p_{CO_2}^{eq}=1.59atm$

Which was clearly defined above.

Best regards.

8 0

3 years ago

An organism's body is constructed using the information contained in

leonid [27]

Gonna have to go with A since two genes create a new one example is parents having a kid that’s how I understood it sorry if it’s wrong or I misunderstood

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3 years ago