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2 years ago

. How many ethyl groups are in the molecule 3, 3-diethylpentane?

Chemistry

1 answer:

Mamont248 [21]2 years ago

6 0

Answer:

2 groups

Explanation:

The molecule 3, 3-diethylpentane has 2 ethyl groups because the prefix di- means that there are 2 homogeneous substituent groups present in the molecule.

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What is the percent lithium in lithium nitrate?

seropon [69]

Answer:

Around 60%

Explanation:

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3 years ago

When sodium is put in water, the metal floats on the surface and reacts to form sodium

mrs_skeptik [129]

Answer: Sodium also floats on the surface, but enough heat is given off to melt the sodium (sodium has a lower melting point than lithium and the reaction produces heat faster) and it melts almost at once to form a small silvery ball that dashes around the surface.

Explanation:

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3 years ago

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How can a Hydrogen atom turn into a<br> Hydrogen ion (H+)?

Butoxors [25]

Answer:

By losing an electron

Explanation:

Electrons have a negative charge. So, losing one would give an element a more positive charge. You can usually find a hydrogen ion (H+) in substances like acids.

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3 years ago

Based on the following thermodynamic data, calculate the boiling point of ethanol in degrees Celsius. Substance ΔH∘f (kJ/mol) S∘

levacccp [35]

Answer:

76.03 °C.

Explanation:

Equation:

C2H5OH(l) --> C2H5OH(g)

ΔHvaporization = ΔH(products) - ΔH (reactants)

= (-235.1 kJ/mol) - (-277.7 kK/mol)

= 42.6 kJ/mol.

ΔSvaporization = ΔS(products) - ΔS(reactants)

= 282.6 J/K.mol - 160.6 J/K.mol

= 122 J/K.mol

= 0.122 kJ/K.mol

Using gibbs free energy equation,

ΔG = ΔH - TΔS

ΔG = 0,

T = ΔH/ΔS

T = 42.6/0.122

= 349.18 K.

Coverting Kelvin to °C,

= 349.18 - 273.15

= 76.03 °C.

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3 years ago

A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?

Oksana_A [137]

Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

$\frac{V1}{T1} = \frac{V2}{T2} \\ \\ T2= \frac{V2*T1}{V1}= \frac{235 mL * 105 ^{\circ}C }{455 mL}=54,23 ^{\circ}C$

So, the final temperature is 54,23 °C

Have a nice day!

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4 years ago

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