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4 years ago

Which of the following processes involves an increase in entropy?

Chemistry

2 answers:

balandron [24]4 years ago

8 0

Melting gold bars is the process that involves an increase in entropy

maria [59]4 years ago

7 0

Answer: melting gold bars

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

1. Condensing water vapor: gaseous phase is being converted to liquid phase, thus the randomness is decreasing.

2. Melting gold bars: Solid phase is being converted to liquid phase, thus the randomness is increasing.

3. filtering grounds from coffee: The randomness is decreasing as some particles are being removed.

4. freezing popsicles: liquid phase is converting to solid phase, thus the randomness is decreasing.

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Elements 3 to 10 (Li to Ne) show a more or less steady increase in IE. What does this tell you about the energy level that each

Karo-lina-s [1.5K]

Elements 3 to 10 (Li to Ne) show a more or less steady increase in ionization energy.

<h3>What is ionisation energy?</h3>

The amount of energy required to remove an electron from an isolated atom or molecule.

The major difference is the increasing number of protons in the nucleus as you go from lithium to neon. That causes greater attraction between the nucleus and the electrons and so increases the ionization energies. In fact the increasing nuclear charge also drags the outer electrons in closer to the nucleus.

Learn more about the ionisation energy here:

brainly.com/question/20658080

#SPJ1

6 0

2 years ago

What are the two kinds of electricity?

xxMikexx [17]

Answer:

4.Current and static electricity

Explanation:

4 0

3 years ago

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

a. Calculate the pH of a solution that has [H3O+]= 4.3 x 10-5 M. b. Is the solution acidic or basic? How do you know?

Luda [366]

Answer:

* $pH=4.37$

* The solution is acidic since the pH is below 7.

Explanation:

Hello,

In this case, we can mathematically define the pH by:

$pH=-log([H_3O^+])$

Thus, for the given hydronium concentration we simply compute the pH:

$pH=-log(4.3x10^{-5})=4.37$

Thereby, we conclude the solution is acidic due to the fact that the pH is below 7 which is the neutral point and above it the solutions are basic.

Regards.

3 0

3 years ago

(3 Points)

prisoha [69]

Your answer is B. radio waves have shorter wavelenghts than microwaves.
Have a great day

5 0

3 years ago

Read 2 more answers