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3 years ago

Which of the following processes involves an increase in entropy?

Chemistry

2 answers:

balandron [24]3 years ago

8 0

Melting gold bars is the process that involves an increase in entropy

maria [59]3 years ago

7 0

Answer: melting gold bars

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

1. Condensing water vapor: gaseous phase is being converted to liquid phase, thus the randomness is decreasing.

2. Melting gold bars: Solid phase is being converted to liquid phase, thus the randomness is increasing.

3. filtering grounds from coffee: The randomness is decreasing as some particles are being removed.

4. freezing popsicles: liquid phase is converting to solid phase, thus the randomness is decreasing.

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A topographical map would be useful for which activity? A. planning a hiking trip B. studying plant growth over time C. studying

amm1812

The answer is A. planning a hiking trip

A topographical map would not help studying plant growth over time unless you are looking for a better altitude to plant said plants.

A topographical map would not help studying rainfall for one year unless your location was really so high or low that it affected your weather

And most of all, a topographical map would not be useful for planning a cuise across the Atlantic Ocean because the elevation of the sea is zero!

A topographical map would be useful for planning a hiking trip because there are many factors and details that a hike should have. Which includes height, distance, paths, and elevation.

5 0

3 years ago

At 40 mph, how long does it take to travel 64 miles

gogolik [260]

1.5 hours
explanation: don’t have one just trust me

6 0

2 years ago

You are working in your laboratory and decide to do some cleaning. You find a test tube with some brown substance congealed at t

Anna [14]

Answer:

The mystery substance is C. Bromine (Br)

Explanation:

Argon (Ar) is a noble gas. Whose freezing point is -189 °C (very low), thus it cannot be the frozen substance. Also, it is not reactive, thus is would have not reacted with iron. Hence, argon is not the mystery substance.

Scandium (Sc) is a metal from group 3 of the periodic table, thus is will not react with iron. Thus, scandium is not the mystery substance.

Both bromine and iodine are halogens (group 17 of the periodic table).

The freezing point of bromine is −7.2 °C, and the freezing point of iodine is 113.7 °C. Thus, both could be solids (frozen) in the lab.

The reactivity of the halogens decrease from top to bottom inside the group. Bromine is above iodine. Then bromine is more reactive than iodine.

Bromine is reactive enough to react with iron. Iodine is not reactive enough to react with iron.

You can find in the internet that bromine vapour over hot iron reacts producing iron(III) bromide. Also, that bromine vapors are red-brown.

Therefore, the mystery substance is bromine (Br).

7 0

3 years ago

Hypercalcemia sign and symptoms severe symptoms

Yuki888 [10]

Answer:

Hypercalcemia can cause stomach upset, nausea, vomiting and constipation. Bones and muscles. In most cases, the excess calcium in your blood was leached from your bones, which weakens them. This can cause bone pain and muscle weakness.

Some symptoms are:

Fatigue, bone pain, headaches.

Nausea, vomiting, constipation, decrease in appetite.

Forgetfulness.

Lethargy, depression, memory loss or irritability.

Muscle aches, weakness, cramping and/or twitches.

5 0

2 years ago

For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an

Mnenie [13.5K]

Answer: 1) $2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

$K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}$

where [] = concentration in Molarity= $\frac{moles}{\text {Volume in L}}$

Thus $[H_2S]=\frac{68.5}{1.0}=68.5M$

$[H_2]=\frac{0.50}{1.0}=0.50M$

$[S_2]=\frac{0.020}{1.0}=0.020M$

$K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450$

As the value of K is greater than 1, the reaction is product favored.

2) $N_2O_4(g)\rightleftharpoons 2NO_2(g)$

$K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}$

$K_{eq}=\frac{[0.500]^2}{[0.0250]}=10$

3) $N_2+3H_2\rightleftharpoons 2NH_3$

$K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.

3 0

2 years ago

Read 2 more answers