The volume of a gas that is required yo react with 4.03 g mg at STP is 1856 ml
calculation/
- calculate the moles of Mg used
moles=mass/molar mass
moles of Mg is therefore=4.03 g/ 24.3 g/mol=0.1658 moles
- by use of mole ratio of Mg:O2 from the equation which is 2:1
the moles 02=0.1679 x1/20.0829 moles
- at STP 1 mole of a gas= 22.4 l
0.0895 moles=? L
- =0.0895 moles x22.4 l/ 1 mole=1.8570 L
into Ml = 1.8570 x1000=1856 ml approximately to 1860
It depends on the concentration of ions which are responsible for the electrical conductivity in aqueous solutions.
Answer:
PV=nRT
Explanation:
V=<u>R</u><u>T</u><u>n</u>
P
rearrangement gives
nT
where P=pressure
V=volume
n=number of moles
R=ideal gas(0.0820atmdm/3 mol/k)
T=temperature in kelvin
Answer:
5 m/s 2
Explanation:
if the car moved from 00 to 1-5 then to 2_10 you can know that it is going up in velocity but 5 a second so 5 m a second. hope this helps
Answer:
كىتى
Explanation:
ؤكىتسؤكى سكتؤىسى شؤت سؤتنى،آ}تسى}