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ipn [44]
3 years ago
7

PLEASE HELP

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
6 0

Answer:

The answer is B.

Explanation:

Trust me i took the test already its b.

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Assume the volume of the crew cabin is 74,000 L. The pressure is maintained at around 1.00 atm, ideally with an 80% nitrogen and
hjlf

Answer:

The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles

Explanation:

The given parameters are;

Volume of the crew cabin = 74,000 L

Pressure of the crew cabin = 1.00 atm

Percentage of nitrogen in the mixture of gases in the cabin = 80%

Percentage of oxygen in the mixture of gases in the cabin = 20%

Temperature of the cabin = 20°C = 293.15 K

Therefore, volume of oxygen in the crew cabin = 20% of 74,000 L

Hence, volume of oxygen in the crew cabin = \frac{20}{100} \times 74,000 \, L = 14,800 \, L

From the universal gas equation, we have;

n = \frac{P \times V}{R  \times  T}

Where:

n = Number of moles  of oxygen

P = Pressure = 1.00 atm

V = Volume of oxygen = 14,800 L

T = Temperature = 293.15 K

R = Universal Gas Constant = 0.08205 L·atm/(mol·K)

Plugging in the values, we have;

n = \frac{1 \times 14,800 }{0.08205   \times  293.15 } = 615.309 \, moles

The number of moles of oxygen present in the crew cabin at any given time = 615.309 moles.

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