“An aquifer is an underground layer of water-bearing permeable rock, rock fractures or unconsolidated materials (gravel, sand, or silt). Groundwater can be extracted using a water well. The study of water flow in aquifers and the characterization of aquifers is called hydrogeology.”
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The second reaction with the volume of 5L will occur faster as compared to the first reaction of volume 10L.
Volume is inversely proportional to the rate of reaction.
As volume increases rate of reaction decreases and as volume decreases rate of reaction increases.
Let's consider a reaction A → B.
r is rate of reaction and K is rate constant, A is the concentration of reaction.
r = k(A)
r is directly proportional to the A.
But the concentration of A is in Moles/liters (i.e. moles per unit volume)
r is inversely proportional to the volume of vessel or chamber.
Hence as volume increases rate of reaction decreases.
For study more about reaction rate refer following link brainly.com/question/19513092.
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Answer: covalent bond
Explanation: Yeah that's the answer
Answer:
44.62 kJ
Explanation:
Firstly, we calculate the energy needed to heat the liquid (ethyl alcohol) by using the formula:
Q = m × c × ∆T
Where;
Q = Amount of heat (J)
m = mass (g)
c = specific heat of ethyl alcohol = 2.138 J/g°C
∆T = change in temperature (°C)
According to the information given in this question;
Q = ?, m = 50.0g, ∆T = (78.4°C - 60°C) = 18.4°C
Therefore, using Q = mc∆T
Q = 50 × 2.138 × 18.4
Q (amount of energy needed to heat ethyl alcohol) = 1966.96 J
Next, we calculate and add the amount of heat needed to vaporize by using the formula;
How many kilojoules of energy are required to heat 50.0 g of ethyl alcohol from 60.0 °C to 78.4 °C and vaporize it? The specific heat of ethyl alcohol is heat of vaporization is 853 J/g.
<span>If you overshoot the endpoint in titration of the KHP, an error will happen in your calculations for the molarity of NaOH you are standardizing. For this, a neutralzation reaction happens where amount of acid should be equal to amount of base. Adding more of the base needed to reach the equivalence would mean you have higher volume which will make the calculated concentration of NaOH lesser.</span>
