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guajiro [1.7K]
2 years ago
8

Question 6

Chemistry
1 answer:
jolli1 [7]2 years ago
6 0

The molecular weight of the substance is 30.46 g/mol.

<h3>What is molar mass?</h3>

Molar mass can be defined as the mass is divided by the number of moles of the substance.

Step 1: calculating the moles

Given, the mass is 177 g

Pressure is 1.18 atm.

The volume is 2.30 L

By the formula of ideal gas

\rm PV = nrt\\1.18 \times 2.30 = n \times 8.312 \times 10^-^2 \times 19.0\\\\n = \dfrac{8.312 \times 10^-^2 \times 19.0}{1.18 \times 2.30} = 0.581 \;mol

Step2 -calculate the molecular weight

The moles are 0.581

\rm Molar\;mass = \dfrac{mass}{number\;of\;moles} \\\\\rm Molar\;mass = \dfrac{17.7g}{0.581} = 30.46

Thus, the molecular weight is 30.46 g/mol

Learn more about molar mass

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3 years ago
0.58 mol of Mg contains how many atoms? please show work
Jet001 [13]

The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms

<h3>Avogadro's hypothesis </h3>

1 mole of Mg = 6.02×10²³ atoms

<h3>How to determine the atoms in 0.58 mole of Mg </h3>

1 mole of Mg = 6.02×10²³ atoms

Therefore,

0.58 mole of Mg = 0.58 × 6.02×10²³

0.58 mole of Mg = 3.49×10²³ atoms

Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg

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3 0
2 years ago
100 POINTS ANSWER FAST
andreev551 [17]
I would say b is the correct answer 
6 0
3 years ago
Read 2 more answers
An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for
Lera25 [3.4K]

Answer:

100.5 ≈ 101

Explanation:

Km for S1 = 2.0 mM

Km for S2 = 20 mM

Given that : S1 = S2 =  hence Vmax for either S1 or S2 can represent

The Vmax can be calculated using the data Given and equation below

Vo = Vmax [s] / ( Km + [s] )  ------ (1)

Vo = 0.5

[s] = 0.1 mM

km = 20 mM

making Vmax subject of  equation 1

Vmax = 0.5 ( 20.1 mM) / (0.1 mM )

         = 100.5 ≈ 101

3 0
3 years ago
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