Well because the lowest possibility of having a decen is 3-decene so 6-decene is not possible. Hope this helps!! :)
The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms
<h3>Avogadro's hypothesis </h3>
1 mole of Mg = 6.02×10²³ atoms
<h3>How to determine the atoms in 0.58 mole of Mg </h3>
1 mole of Mg = 6.02×10²³ atoms
Therefore,
0.58 mole of Mg = 0.58 × 6.02×10²³
0.58 mole of Mg = 3.49×10²³ atoms
Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg
Learn more about Avogadro's number:
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I would say b is the correct answer
Answer:
100.5 ≈ 101
Explanation:
Km for S1 = 2.0 mM
Km for S2 = 20 mM
Given that : S1 = S2 = hence Vmax for either S1 or S2 can represent
The Vmax can be calculated using the data Given and equation below
Vo = Vmax [s] / ( Km + [s] ) ------ (1)
Vo = 0.5
[s] = 0.1 mM
km = 20 mM
making Vmax subject of equation 1
Vmax = 0.5 ( 20.1 mM) / (0.1 mM )
= 100.5 ≈ 101