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sukhopar [10]
3 years ago
14

What happens when you add acetic acid vinegar and sodium bicarbonate baking soda nahco​

Chemistry
1 answer:
Sophie [7]3 years ago
8 0

Explanation:

oh shi sorry I wish I could help but I'm stupid

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Rank the effective nuclear charge Z* experienced by a valence electron in each of these atoms:
lozanna [386]

Answer:

Si > Al > Mg > Na

Explanation:

In an atom, there is the positively charged particle' the proton, the negatively charged particle; the electron and neutral charged particle; the neutron. The effect of the proton on an atom that is the ability of these positive particles to attract the negative[valence electrons] particles is known as Effective nuclear charge.

[1]. Electron configuration of Silicon, Si = (1s²2s²2p⁶) 3s²3p².

The configuration part of Si in bracket is known as the inner electrons while the ones without brackets are the outer/valence electrons.

The total number of electrons = 14, the inner electrons= 10. Thus,  effective nuclear charge = 14 - 10 = 4.

[2]. Electron configuration of Aluminum, Al = (1s²2s²2p⁶) 3s²3p¹.

The configuration part of Al in bracket is known as the inner electrons while the ones without brackets are the outer/valence electrons.

The total number of electrons = 13, the inner electrons= 10. Thus,  effective nuclear charge = 13 - 10 = 3.

[3]. Electron configuration of Magnesium, Mg = (1s²2s²2p⁶) 3s²

The configuration part of Mg in bracket is known as the inner electrons while the ones without brackets are the outer/valence electrons.

The total number of electrons = 12, the inner electrons= 10. Thus,  effective nuclear charge = 12 - 10 = 2.

[4]. Electron configuration of sodium, Na = (1s²2s²2p⁶) 3s¹.

The configuration part of Na in bracket is known as the inner electrons while the ones without brackets are the outer/valence electrons.

The total number of electrons = 11, the inner electrons= 10. Thus,  effective nuclear charge = 11 - 10 = 1.

8 0
3 years ago
Which of the following levels of classification is the most specific?
Artemon [7]

it would be species in this case


8 0
3 years ago
Read 2 more answers
Determine if the results of the following word problem adhere to the Law of Conservation of Mass. 1. A chemist combines 4.9 g of
KiRa [710]

Answer: The results agree with the law of conservation of mass

Explanation:

The law of conservation of mass states that mass is neither created nor destroyed in a chemical reaction. On the reactant side, the total mass of reactants is 14.3g and the total product masses is also 14.3g. That implies that no mass was !most in the reaction. The sum of masses on the left hand side corresponds with sum of masses on the right hand side of the reaction equation.

4 0
3 years ago
How can u describes a true solution?
zubka84 [21]
<span>True Solution is a homogeneous mixture of two or more substances in which substance dissolved (solute) in solvent has the particle size of less than 10-9 m or 1 nm. Simple solution of sugar in water is an example of true solution.</span>
5 0
3 years ago
Calculate the equilibrium concentration of H 3 O H3O in a 0.20 M M solution of oxalic acid. Express your answer to two significa
Black_prince [1.1K]

<u>Answer:</u> The equilibrium concentration of H_3O^+ ion is 8.3064\times 10^{-2}M

<u>Explanation:</u>

We are given:

Molarity of oxalic acid solution = 0.20 M

Oxalic acid (H_2C_2O_4) is a weak acid and will dissociate 2 hydrogen ions.

  • The chemical equation for the first dissociation of oxalic acid follows:

               H_2C_2O_4(aq.)+H_2O\rightleftharpoons H_3O^+(aq.)+HC_2O_4^-(aq.)

<u>Initial:</u>        0.20

<u>At eqllm:</u>    0.20-x                            x                 x

The expression of first equilibrium constant equation follows:

Ka_1=\frac{[H_3O^+][HC_2O_4^{-}]}{[H_2C_2O_4]}

We know that:

Ka_1\text{ for }H_2C_2O_4=0.059

Putting values in above equation, we get:

0.059=\frac{x\times x}{(0.20-x)}\\\\x=-0.142,0.083

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = x = 0.083 M

  • The chemical equation for the second dissociation of oxalic acid:

                 HC_2O_4^-(aq.)+H_2O\rightarrow H_3O^+(aq.)+C_2O_4^{2-}(aq.)

<u>Initial:</u>         0.083  

<u>At eqllm:</u>    0.083-y                      0.083+y               y

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H_3O^+][C_2O_4^{2-}]}{[HC_2O_4^-]}

We know that:

Ka_2\text{ for }H_2C_2O_4=6.4\times 10^{-5}

Putting values in above equation, we get:

6.4\times 10^{-5}=\frac{(0.083+y)\times y}{(0.083-y)}\\\\y=-0.083,0.0000639

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = y = 0.0000639 M

Total concentration of hydronium ion = [x + y] = [0.083 + 0.0000639] = 0.0830639 M

Hence, the equilibrium concentration of H_3O^+ ion is 8.3064\times 10^{-2}M

7 0
3 years ago
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