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inna [77]
4 years ago
13

Match the following descriptions with the correct polysaccharide, note if you answer any part of this question incorrectly a sig

n read x will appears if one or more of the polysaccharides placed in correctly This polysaccharide is the storage form of glucose in the human body. This polysaccharide is the structural component of plant cell walls and cannot be digested by humans. The glucose units in this polysaccharide are joined only by 1,4glycosidic bonds glycogen The glucose units in this polysaccharide are joined by beat.1,4-glycosidic bonds Those two branched polysaccharides contain both alpha 1.4 and alpha 1,6-glycosidic bonds These two polysaccharides make up starch, the storage form of glucose in plants
Chemistry
1 answer:
Ad libitum [116K]4 years ago
4 0

Answer:

Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.

Explanation:

Glycogen is the form that glucose is stored in human body.

Cellulose is the structural part of plant cell walls and human cannot digest it.

Amylose is the polysaccharide linked mainly by the the bonds of \alpha 1,4 glycosidic.

Cellulose is an unbranched polysaccharide linked mainly by the bonds of  \beta 1,4 glycosidic.

Amylopetin and Glycogen are branched polysaccharides linked by the bonds of \alpha 1,4 glycosidic and \alpha 1,6 glycosidic.

Amylopetin and Cellulose are mainly stored in plants.

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To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o
Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

r=\frac{d}{2}

=\frac{3.36x10^{2}}{2}

= 168 m

Volume =

=\frac{22\times 168^{2}\times 21.80}{7}

=1.93\times 10^{6} m^{3}

2.Convert ppm to g/m3 and Solve for mass of F-

1ppm = 1g/m^{3}

0.9ppm = 0.9g/m^{3}

Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}

mass\ of\ F- =1.740g

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0
3 years ago
The mass in grams of C in 275 g of C3H6
Furkat [3]

Answer:

Mass of carbon = 236.5 g

Explanation:

Given data:

Mass of C₃H₆ = 275 g

Mass of C = ?

Solution:

Formula:

Mass of carbon =  molar mass of carbon/ molar mass of compound × mass of compound

Molar mass of carbon = 12 g/mol

Molar mass of compound = 42 g/mol

Mass of carbon = 36 g/mol / 42 g/mol × 275 g

Mass of carbon = 0.86 × 275 g

Mass of carbon = 236.5 g

3 0
3 years ago
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Some elements that are not abbreviated with one or two letters on the periodic table are Ununoctium (Uuo) and Ununtrium (Uut).
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