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inna [77]
3 years ago
13

Match the following descriptions with the correct polysaccharide, note if you answer any part of this question incorrectly a sig

n read x will appears if one or more of the polysaccharides placed in correctly This polysaccharide is the storage form of glucose in the human body. This polysaccharide is the structural component of plant cell walls and cannot be digested by humans. The glucose units in this polysaccharide are joined only by 1,4glycosidic bonds glycogen The glucose units in this polysaccharide are joined by beat.1,4-glycosidic bonds Those two branched polysaccharides contain both alpha 1.4 and alpha 1,6-glycosidic bonds These two polysaccharides make up starch, the storage form of glucose in plants
Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.

Explanation:

Glycogen is the form that glucose is stored in human body.

Cellulose is the structural part of plant cell walls and human cannot digest it.

Amylose is the polysaccharide linked mainly by the the bonds of \alpha 1,4 glycosidic.

Cellulose is an unbranched polysaccharide linked mainly by the bonds of  \beta 1,4 glycosidic.

Amylopetin and Glycogen are branched polysaccharides linked by the bonds of \alpha 1,4 glycosidic and \alpha 1,6 glycosidic.

Amylopetin and Cellulose are mainly stored in plants.

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12 mph

Explanation:

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The equilibrium constant for the reaction
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The question is incomplete, here is the complete question:

The equilibrium constant for the reaction

N₂O₄(g)⇌2NO₂ at 2°C is Kc = 2.0

If each yellow sphere represents 1 mol of N₂O₄(g) and each gray sphere 1 mol of NO₂ which of the following 1.0 L containers represents the equilibrium mixture at 2°C?

The image is attached below.

<u>Answer:</u> The system which represents the equilibrium having value of K_c=2.0 is system (b)

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{c} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

N_2O_4(g)\rightleftharpoons 2NO_2

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}      .......(1)

We are given:

Volume of the container = 1.0 L

Value of K_c = 2.0

Molarity of the substance is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

For the given images:

  • <u>For a:</u>

Number of Gray spheres = 8 moles

Number of yellow spheres = 4 moles

Putting values in expression 1, we get:

K_c=\frac{(8/1)^2}{(4/1)}\\\\K_c=16

  • <u>For b:</u>

Number of Gray spheres = 4 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(4/1)^2}{(8/1)}\\\\K_c=2

  • <u>For c:</u>

Number of Gray spheres = 6 moles

Number of yellow spheres = 6 moles

Putting values in expression 1, we get:

K_c=\frac{(6/1)^2}{(6/1)}\\\\K_c=6

  • <u>For d:</u>

Number of Gray spheres = 2 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(2/1)^2}{(8/1)}\\\\K_c=\frac{1}{2}

Hence, the system which represents the equilibrium having value of K_c=2.0 is system (b)

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3 years ago
Explain the process of radioactive decay. What happens during the radioactive decay? What is the result at the end of radioactiv
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For example, in alpha decay atom transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

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Answer:

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Explanation:

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C =nq

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