The addition of catalyst in a chemical reaction has 2 functions
1. if you add negative catalyst then the rate of chemical reaction decreases
2. if you add positive catalyst then the rate of chemical reaction increases.

6 0

4 years ago

What volume of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to wate

8_murik_8 [283]

Answer:

200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water.

Explanation:

The solution is the result of the mixture between the solute, which is the substance that dissolves, and the solvent, which is the substance in which a solute dissolves. That is, a solution (or solution) is a mixture of two or more components, perfectly homogeneous since each component is intimately mixed with the other.

The concentration of solutions is the amount of solute contained in a given amount of solvent or solution. A unit of concentration is the percent weight to volume.

The percent weight to volume is the percentage ratio between the weight of the solute and the volume of the solution. It is calculated as:

$Percent =\frac{mass of solute}{volume of solution} *100$

Mass is measured in grams, while volume is measured in mL.

In this case:

Percent weight to volume= 6%
mass of solute= 12 g
volue of solution= ?

Replacing:

$6=\frac{12 g}{volume of solution} *100$

Solving:

volume of solution*6= 12 g*100

$volume of solution=\frac{12 g}{6} *100$

volume of solution= 200 mL

200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water

8 0

3 years ago

A current theory states during Earth’s formation, it was struck by a planet approximately the same size as Mars. Select the foll

Ivanshal [37]

Answer:

the earth gained mass from the impact :)

welcome

7 0

3 years ago

In order to gain one pound of body weight, the average person must consume 3500 more calories

Fed [463]

Answer:

17500 calories of chocolate bars are needed to eat to gain 5 pounds.

Explanation:

We can use ratios to calculate the answer using the information given in the question.

1 pound : 3500 grams

5 pounds : x grams

As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.

Method A:

To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.

x = 3500 × 5

x = 17500

Method B:

To solve for the answer x, we can convert the ratios into fractions.

1 / 5 = 3500 / x

3500 / x = 1 / 5

To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.

x = 5 × 3500

x = 17500

4 0

4 years ago