Molar mass of glucose = 180 g/mol
moles = mass / molar mass.
hence moles of glucose added = 13.5 g / (180 g/mol) = X mol
those moles in 100.0 mL of solution.
Hence moles in 55.0 mL = (X mol x 55.0 mL) / 100.0 mL
that 55.0 mL was diluted to 0.500 L (500 mL)
Hence glucose moles in 500 mL = moles in 55.0 mL
= (X mol x 55.0 mL) / 100.0 mL
Final 100.0 mL was taken from the diluted solution.
Hence moles in final 100.0 mL = ((X mol x 55.0 mL) / 100.0 mL) x (100.0 mL) / 500.0 mL
= X x 11 / 100
Glucose mass in final 100.0 mL = X x 11 / 100 mol x 180 g/mol
= 1.485 g
Answer:
C.Sound waves.
<h2>Hope it helps you.</h2>
There are ten dL in one litre, so an ideal amount of lead in a litre of blood would be no greater than 400 micrograms (ug)
There's 1000mL in a litre, so we're looking at 0.4ug of lead or less in a millilitre. 1mol of lead atoms weighs about 207.2g, therefore there's about 2.907 × 10^21 atoms per gram, or about 1.163×10^14 atoms in 0.04ug. Therefore there should be no more than 1.2×10^14 atoms of lead per millilitre.
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