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astraxan [27]
2 years ago
13

Hydrogen gas and solid gold(III) sulfide are reacted. Pure solid gold metal is formed and gaseous hydrogen sulfide is released.

Correctly identify the reactants and products:reactants:
a. solid gold, gaseous hydrogen sulfideproducts: hydrogen gas, solid gold(III)
b. sulfidereactants: solid gold, solid gold(III) sulfideproducts: hydrogen gas, gaseous
c. hydrogen sulfidereactants: hydrogen gas, solid gold, gaseousproducts: hydrogen sulfide
d. solid gold(III) sulfidereactants: hydrogen gas, solid gold(III)
e. sulfide products: solid gold, gaseous hydrogen sulfide
Chemistry
1 answer:
alexdok [17]2 years ago
8 0

The reactants of the reaction will be solid gold (III) sulfide and hydrogen gas, while the products will be pure solid gold and hydrogen sulfide gas.

<h3>Chemical reactions</h3>

Reactants react together during reactions to arrive at products.

In this case, solid gold (III) sulfide and hydrogen gas react according to the following equation:

Au_2S_3(s) + 3 H_2 (g)-- > 2 Au(s) + 3H_2S(g)

Reactants = solid gold (III) sulfide, hydrogen gas

Products: pure solid gold, hydrogen sulfide gas

More on chemical reactions can be found here: brainly.com/question/1689737

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