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Pavlova-9 [17]
3 years ago
12

What is the percent composition for the compound NaBr? (8C)

Chemistry
1 answer:
ehidna [41]3 years ago
3 0

Answer:

the answer is D

Explanation:

percentage composition=  mole of the substance divided by the total molar mass of the compound multiplied by 100.

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Show how acid and base give below dissociates in water <br>HNO3​
lara31 [8.8K]
The answer is b thank me later :)
3 0
3 years ago
To determine the concentration of a sample of calcium hydroxide, 1.45M HCl is added drop-wise using a burst. Write the balanced
GenaCL600 [577]

Answer:

H^+(aq) + OH^-(aq) —> H2O(l)

Explanation:

We'll begin by writing the balanced equation for the reaction.

2HCl(aq) + Ca(OH)2(aq) —> CaCl2(aq) + 2H2O(l)

Ca(OH)2 is a strong base and will dissociates as follow:

Ca(OH)2(aq) —> Ca^2+(aq) + 2OH^-(aq)

HCl is a strong acid and will dissociates as follow:

HCl(aq) —> H^+(aq) + Cl^-(aq)

Thus, In solution a double displacement reaction occurs as shown below:

2H^+(aq) + 2Cl^-(aq) + Ca^2+(aq) + 2OH^-(aq) —> Ca^2+(aq) + 2Cl^-(aq) + 2H2O(l)

To get the net ionic equation, cancel out Ca^2+ and 2Cl^-

2H^+(aq) + 2OH^-(aq) —> 2H2O(l)

H^+(aq) + OH^-(aq) —> H2O(l)

7 0
3 years ago
The following ionization energies were found for an unknown element: -
Alika [10]

Answer:

The common ion will be di-positive ion.

Explanation:

The ionization energy is defined as the amount of energy needed for removal of most loosely bound electron from an isolated atom in gaseous state.

The low ionization energy shows that the atom is able to give electron easily as after losing electron it may attain noble gas configuration or half filled stability.

Here the first and second ionization energy, both are low suggesting that the element is ready to give two electrons easily to form a di-positive ion however the third ionization energy is high which shows that it will not form tri-positive ion commonly.

7 0
3 years ago
Determine the empirical formula of a compound containing 1.71 g of silicon and 8.63 g of chlorine.
Basile [38]

Answer:

The answer to your question is: SiCl₄

Explanation:

Data

amount of Si      1.71 g

amount of Cl     8.63 g

MW Si = 28 g

MW Cl = 35.5

Process (rule of three)

For Si                                                        For Cl

        28 g of Si ------------------ 1 mol                      35.5 g of Cl --------------- 1 mol

          1.71g of Si  ---------------   x                              8.63 g of Cl --------------  x

         x = 1.71 x 1 / 28 = 0.06 mol                          x = 8.63 x 1 / 35.5 = 0.24 mol

Now, divide both results by the lowest of them.

Si = 0.06 mol / 0.06 = 1 molecule of Si     Cl = 0.24 / 0.06 = 4 molecules of Cl

Finally

                     Si₁ Cl₄ or SiCl₄

8 0
3 years ago
If 33.6 grams of kcl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? 21.2% kc
trapecia [35]
Ms ( mass of solute): 33,6g
mss (mass of solution): 33,6+192g = 225,6g
__________________
C = ms/mss × 100%
C = 33.6/225.6 × 100%
C = 14,89% ≈ 14,9%

:•)
4 0
3 years ago
Read 2 more answers
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