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Andrej [43]
2 years ago
5

When a skateboarder rides down a hill, the normal force exerted on the skater by the hill is

Physics
1 answer:
Luda [366]2 years ago
3 0

Newton's second law allows us to find that the correct answer is:

  • Less than weight of the skater

Newton's second law states that the net force and is propositional to the mass and acceleration of the body

For these problems it is essential to set a reference system, with respect to which to carry out the measurements, in this case we set a coordinate system with the x axis parallel to the plane and positive in the direction of movement and the y axis perpendicular to the plane.

In the attachment we can see a free-body diagram of the problem, let's work each axis separately

x-axis

         Wₓ -fr = m a

y-axis

         N - W_y = 0

         N = W_y

Where Wₓ and W_y are the components of the weight, fr the friction force that opposes the movement, m the mass and the acceleration of the body

let's use trigonometry to find the components of the weight

        cos θ = \frac{W_y}{W}

        sin θ = \frac{W_x}{W}

         W_y = W cos θ

         Wₓ = W sin θ

we substitute

          N = mg cos θ

From this equation we can see that the normal is less than the weight of the body.

In conclusion using Newton's second law we find that the correct answer is:

  • Less than th weight of the skater

 

Learn more about Newton's second law here:

brainly.com/question/13685393

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1 we see that the ray deviation is promotional to the ratio of the refractive indices

The order of refraction is a, e, de, c

.b) When a ray passes from a medium with less indicated refraction to a higher index the part of the reflected ray has a phase change of 180º

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b) reflected ray has a phase change of 180º

c) no phase change

d) no phase change

e) there is a phase change

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