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Anna11 [10]
3 years ago
9

Runoffs from an uranium mine stockpile have contaminated the surface water in a location. This might cause health problems among

people in the location. Which of these is the best plan to solve this problem?
Select one:
a. plant trees around uranium mines to absorb contaminants
b. put fences around uranium mines to check the flow of contaminants
c. wear protective clothing for prevention against harmful effects of radiation
d. collect the runoffs in retention ponds for isolation and recovery of contaminants
Physics
1 answer:
xz_007 [3.2K]3 years ago
3 0

The best plan to solve the problem of health problems among people, because of the contaminated surface water is to collect the runoffs in retention ponds for isolation and recovery of contaminants. Correct answer: D

This is tn eonly option from the given that is the most efficient and prodcutive way to solve this problem.


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Would you expect to weigh more on an ocean beach or on top of a mountain? Explain.
frosja888 [35]

Answer:

An Ocean beach

Explanation:

a Ocean beach is far heavier than the top of a mountain, despite that a mountain is made with many heavy rocks a Ocean beach may have light sand but the layers of sand and the width would be way heavier then the top of a mountain.

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Jenny and Alyssa are members of the cross-country team. On a training run, Jenny starts off and runs at a constant 3.8 m/s. Alys
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Answer:

285 seconds

Explanation:

Jenny speed is 3.8 m/s

Alyssa speed in 4.0 m/s

Alyssa starts after 15 seconds

Find the distance covered by Jenny, when Alyssa starts

Distance=Speed*time

Distance covered by Jenny in 15 seconds= 3.8×15=57m

Relative speed of the two members heading same direction will be;

4.0m/s-3.8m/s=0.2m/s

To find the time Alyssa catch up with Jenny you divide the distance to be covered by Alyssa by the relative speed of the two

Distance=57m, relative speed=0.2m/s  t=57/0.2 =285 seconds

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Convert 2kg into SI unit of force​
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Answer:

19.6133 newton.

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3 years ago
A 16.5-kg crate starts at rest at the top of a 60.0° incline. The coefficients of friction are μs = 0.400 and μk = 0.300. The cr
irga5000 [103]

Answer:

t = 1.62 s

Explanation:

given,

mass of the block m₁ = 16.5 Kg

m₂ = 8 Kg

angle of inclination = 60°

μs = 0.400 and μk = 0.300

time to slide 2 m = ?

a) let a is the acceleration of the block m₁ downward.

Net force acting on m₂,

F₂ = T - m₂ g

m₂a = T - m₂ g

a = \dfrac{T}{m_2} - g.......(1)

net force acting on m₁

F₁ = m₁g sin(60°) - μ_k m₁g cos (60°) - T

m₁ a = m₁g sin(60°) - μ_k m₁g cos (60°) - T

a = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}.........(2)

from equations 1 and 2

\dfrac{T}{m_2} - g = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}

\dfrac{T}{m_2} +\dfrac{T}{m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)

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T = {16.5\times 8}\dfrac{9.8 + 9.8 sin(60^0) - 0.3\times 9.8 cos (60^0)}{{16.5+8}}

T = 90.61 N

from equation (1)

a = \dfrac{90.61}{8} - 9.8.......(1)

a = 1.52 m/s²

let t is the time taken

Apply,

d = ut + 0.5 a t²

2 = 0 + 0.5 x 1.52 x t²

t = \sqrt{2.63}

t = 1.62 s

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Svet_ta [14]

Answer:

So we have a measure in grams, we can start with something like:

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Then we must write our measurement as:

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Where the digit that came after the 5 was a 2, so we rounded down.

4 0
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