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nikitadnepr [17]
3 years ago
12

Shari uses the data in the table to predict how her weight on Venus would compare with her weight on Earth.

Physics
2 answers:
spin [16.1K]3 years ago
3 0

Answer :  <em>Her weight is lower on Venus because the acceleration due to gravity is lower.</em>

Explanation :

Venus is also called as Earth's twin. This is because both the mass and the size of Earth and Venus are almost same. The acceleration due to gravity on earth is 9.8\ m/s^2 while on Venus is 8.87\ m/s^2.

So, when Shari measure her weight on Venus she found her weight is lower on Venus. This is because the acceleration due to gravity is lower on the surface of Venus as compared to the Earth.

Since,    w=mg

i.e. weight depends on g.

<em>So, correct prediction is (b)</em>

andrey2020 [161]3 years ago
3 0

Answer:

the answer is B

Her weight is lower on Venus because the acceleration due to gravity is lower

Explanation:

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Question 2
Ksivusya [100]

5.77 ×10^1^4 Hz is the green photon's frequency .

The distance between similar points (adjacent crests) in adjacent cycles of a waveform signal that is propagated in space is known as the wavelength. A wave's wavelength is often measured in meters (m), centimeters (cm), or millimeters (mm) (mm). The relationship between frequency and wavelength is inverse.

<h3>Given:</h3>

Wavelength of green light = 520 nm

f = c / λ

where, f = Frequency

            c = Speed of light = 3 × 10^8 m/s

            λ = Wavelength of light

∴ f = c / λ

  f = \frac{3*10^8}{520 * 10^-^9}

    = 5.77 ×10^1^4 Hz

Therefore,  5.77 ×10^1^4 Hz is the green photon's frequency .

Learn more about wavelength here:

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4 0
1 year ago
91.0x26x504 ...............
Hoochie [10]

Answer:

1192464

Explanation:

91.0 times 26 = 2366

2366 times 504 = 1192464

7 0
3 years ago
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Answer:

yes 20 characters or more

Explanation:

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Assume that the home construction industry is perfectly competitive and in long-run competitive equilibrium. It follows that: A.
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B. Marginal cost equals long-run average total cost.

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Changing its velocity

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