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3 years ago

The real number square root of 16 belongs to which sets of numbers?

1 answer:

3 0

Answer: Square root of 16 is +4 or -4. Since -4 is not a natural number, the square root can be described as an integer.

Step-by-step explanation:

The square root of 16 is a rational number. The square root of 16 is 4, an integer

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Can anybody please help me

faltersainse [42]

Answer:

324

Step-by-step explanation:

The shirt would be the same value because they are the same so

288÷3=96

Pi Shirt = 96

then work out the 3rd one to find out the balloons

98+ balloon + balloon= 226-96=130÷2= 65

Balloons = 65

then work out the 2nd one 195÷65=3

Pizza = 3

Then 4th one

25+1=26-3=29

Maccoroni = 29

Last question

96×3+65-29=324

4 0

3 years ago

Expression written using exponents

Scilla [17]

Since there are no specific requirements given other than expression written using exponents, I am just going to give some examples.

1. 5x^2 - 3

2. 8^5 - 15x + 7

3. 15x^10 - 8x^7 + 16x^5 + 17^3 - 4^2 +13x - 2

5 0

3 years ago

A car travels at a constant speed.

ad-work [718]

Answer:

see below

Step-by-step explanation:

<h3>Given</h3>

Distance is 142.2 m, correct to 1 decimal place
Time is 7 seconds, correct to nearest second

Upper bound for the speed

<h3>Solution </h3>

<em>Upper bound for the speed = upper bound for distance/lower bound for time</em>

Upper bound for distance = 142.25 m (added 0.1/5 = 0.05)
Lower bound for time = 6.5 seconds (subtracted 1/2 = 0.5)

<u>Then, the speed is:</u>

142.25/6.5 = 21.88 m/s
21.88 = 21.9 m/s correct to 1 decimal place
21.88 = 22 m/s correct to nearest m/s

4 0

3 years ago

What is 96/104 in simplest form

Alecsey [184]

12/13 I believe :) hope it helps

8 0

3 years ago

Read 2 more answers

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago