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creativ13 [48]
4 years ago
6

A wave has a low speed but a high frequency. What can you infer about its wavelength?

Physics
1 answer:
Vaselesa [24]4 years ago
4 0
The amount of the wave length is inversely proportional to its frequency and directly to its speed. So in your question, the amount of wavelength with a low speed and high frequency has a low value or quality of wavelength output. If your frequency would get high but the speed is just low the wave length is still low
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Globular clusters are important to understanding the Milky Way because Choose one: A. they reveal the size of the Milky Way and
kirill115 [55]

The correct answer is (A) they reveal the size of the Milky Way and Earth's location in it.

<h3>Why are globular clusters important?</h3>

Globular clusters are densely packed groups of old stars. They are roughly spherical in form and contain hundreds of thousands, if not millions, of stars. Studying them can help astronomers determine the age of the universe or locate the core of a galaxy.

According to Georgia State University there are around 150 identified globular clusters in the Milky Way galaxy. Most are thought to be at least 10 billion years old and contain some of the galaxy's oldest stars. The clusters most likely originated relatively early in the galaxy's evolution, before it flattened into a spiral disc.

Some globular clusters, like as Messier 13 (M13) in Hercules, are visible with the eye.

learn more about globular clusters refer:

brainly.com/question/14124832

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5 0
2 years ago
An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s1045 rad/s ). If a particular disk is s
kumpel [21]

To solve this problem we must keep in mind the concepts related to angular kinematic equations. For which the angular velocity is defined as

\omega_f =\omega_i-\alpha t

Where

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

\alpha =Angular acceleration

t= time

In this case we do not have a final angular velocity, then

\omega_i = \alpha t

Re-arrange for \alpha

\alpha= \frac{\omega_i}{t}

\alpha = \frac{910}{0.167}

\alpha = 5449.1 rad\s^2

Therefore the mangitude of the angular aceleration is 5449.1rad/s²

6 0
4 years ago
"a musical tone sounded on a piano has a frequency of 261.6 hz and a wavelength of 1.31 m. what is the speed of the sound wave
Andreyy89
To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.
7 0
3 years ago
Read 2 more answers
i learned that kinetic energy is energy when an object is actually moving not including the moving particles. i also learned tha
GaryK [48]

Answer:

Part of that kinetic energy created by moving of particles in object is transformed to heat that can be measured by thermometer.

Explanation:

By moving object creates kinematic energy, that is true. In object itself small particles are moving and creating kinetic energy as well. Part of that kinetic energy created by moving of particles in object is transformed to heat that can be measured by thermometer.

Same thing is that when you run or exercise your body temperature is raising(because of moving ).

When you sit your body does not raise temperature.

6 0
3 years ago
The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
BigorU [14]

1. Frequency: 7.06\cdot 10^{14} Hz

The frequency of a light wave is given by:

f=\frac{c}{\lambda}

where

c=3\cdot 10^{-8} m/s is the speed of light

\lambda is the wavelength of the wave

In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


4 0
3 years ago
Read 2 more answers
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