The total energy stored in the capacitors is determined as 2.41 x 10⁻⁴ J.
<h3>What is the potential difference of the circuit?</h3>
The potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
where;
- C is capacitance of the capacitor
- V is the potential difference
For a parallel circuit the voltage in the circuit is always the same.
The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
2U = CV²
V = √2U/C
V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)
V = 12 V
The equivalent capacitance of C1 and C2 is calculated as follows;
1/C = 1/C₁ + 1/C₂
1/C = (1)/(0.9 x 10⁻⁶) + (1)/(16 x 10⁻⁶)
1/C = 1,173,611.11
C = 1/1,173,611.11
C = 8.52 x 10⁻⁷ C
The total capacitance of the circuit is calculated as follows;
Ct = 8.52 x 10⁻⁷ C + 2.5 x 10⁻⁶ C
Ct = 3.35 x 10⁻⁶ C
The total energy of the circuit is calculated as follows;
U = ¹/₂CtV²
U = ¹/₂(3.35 x 10⁻⁶ )(12)²
U = 2.41 x 10⁻⁴ J
Learn more about energy stored in a capacitor here: brainly.com/question/14811408
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Answer:
Explanation:
As we know that diameter of hand crank is given as
Also the diameter of the shaft on which the rope is wound is given as
now we know that both are moving with same angular speed
so we will have
so we will have
Answer:
The green car traveled a shorter distance, but the displacement of the cars was equal.
Explanation:
Answer:
Explanation:
The electric field on the surface of a conductor is given by:
Here is the surface charge density and the permittivity of free space. Thus, the highest surface charge density that can exist in a conductor is given by the value of the dielectric breakdown of the air multiplied by the permittivity of free space:
Answer:
(a) v = 32 t
h = 16 t^2
g = 32 ft/s^2
(b) 64 ft/s
Explanation:
height, h = 64 feet
g = - 32 ft/s^2
(a) Let the time is t .
Let the velocity after time t is v.
Use first equation of motion
v = u + at
- v = 0 - 32 t
v = 32 t
Let the distance is h from the top.
Use second equation of motion
The acceleration is constant for entire motion.
(b) Let the velocity is v as it hits the ground. Use third equation of motion