The correct answer is (A) they reveal the size of the Milky Way and Earth's location in it.
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Why are globular clusters important?</h3>
Globular clusters are densely packed groups of old stars. They are roughly spherical in form and contain hundreds of thousands, if not millions, of stars. Studying them can help astronomers determine the age of the universe or locate the core of a galaxy.
According to Georgia State University there are around 150 identified globular clusters in the Milky Way galaxy. Most are thought to be at least 10 billion years old and contain some of the galaxy's oldest stars. The clusters most likely originated relatively early in the galaxy's evolution, before it flattened into a spiral disc.
Some globular clusters, like as Messier 13 (M13) in Hercules, are visible with the eye.
learn more about globular clusters refer:
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To solve this problem we must keep in mind the concepts related to angular kinematic equations. For which the angular velocity is defined as

Where
Final angular velocity
Initial angular velocity
Angular acceleration
t= time
In this case we do not have a final angular velocity, then

Re-arrange for 



Therefore the mangitude of the angular aceleration is 5449.1rad/s²
To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.
Answer:
Part of that kinetic energy created by moving of particles in object is transformed to heat that can be measured by thermometer.
Explanation:
By moving object creates kinematic energy, that is true. In object itself small particles are moving and creating kinetic energy as well. Part of that kinetic energy created by moving of particles in object is transformed to heat that can be measured by thermometer.
Same thing is that when you run or exercise your body temperature is raising(because of moving ).
When you sit your body does not raise temperature.
1. Frequency: 
The frequency of a light wave is given by:

where
is the speed of light
is the wavelength of the wave
In this problem, we have light with wavelength

Substituting into the equation, we find the frequency:

2. Period: 
The period of a wave is equal to the reciprocal of the frequency:

The frequency of this light wave is
(found in the previous exercise), so the period is:
