Answer:
80
Explanation:
<em>the </em><em>mechanical</em><em> </em><em>advantage</em><em> </em><em>is </em><em>the </em><em>ratio </em><em>of </em><em>the </em><em>load </em><em>to </em><em>the </em><em>effort</em><em> </em><em>so </em><em>it </em><em>doesn't</em><em> </em><em>have </em><em>units.</em><em>t</em><em>o</em><em> </em><em>calculate</em><em> </em><em>it </em><em>you </em><em>use </em><em>the </em><em>formula</em>
<em>mechanical</em><em> advantage</em><em>=</em><em>load/</em><em>effort</em>
<em>in </em><em>this</em><em> case</em><em> </em><em>the </em><em>load </em><em>is </em><em>6</em><em>0</em><em>0</em><em>0</em><em>N</em><em> </em><em>and </em><em>the </em><em>effort</em><em> </em><em>is </em><em>7</em><em>5</em><em>N</em>
<em>Ma=</em><em>6</em><em>0</em><em>0</em><em>0</em><em>/</em><em>7</em><em>5</em>
<em>=</em><em>8</em><em>0</em>
<em>I </em><em>hope</em><em> this</em><em> helps</em>
Answer:
L = 130 decibels
Explanation:
The computation of the sound intensity level in decibels is shown below:
According to the question, data provided is as follows
I = sound intensity = 10 W/m^2
I0 = reference level = 
Now
Intensity level ( or Loudness)is




Therefore
L = 13 bel
And as we know that
1 bel = 10 decibels
So,
The Sound intensity level is
L = 130 decibels
Answer:

Explanation:
<u>Average Density
</u>
The density of an object of mass m and volume V is

If we know the density and the volume occupied by the object, the mass can be computed as

The tank can hold 20 L of gasoline when full. Converting to cubic meters

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

To know the total mass of both, we add the 2.5 kg of the tank

The volume of the tank is computed solving for V


The total volume is

The average density is


The condition of earths atmosphere at a given time and place is the weather.
Answer:
B. There is a direct proportion between the mass and force listed in the table.
Explanation:
From the table, the values of force increases with increase in the value of mass.
if 5kg=25 N
Finding the contant of proportionality k;
k=25/5=5
thus M=k(F)...........where M is mass in kg and F is force in newton, then
M=5F
This show that for every value of mass, we get the value of Force if we multiply by a contant k=5
This means there is a direct proportionality relation between mass and force in the table.