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german
3 years ago
15

Which is a sub-atomic particle?

Physics
1 answer:
Natalka [10]3 years ago
4 0
A particle that is smaller than an atom or a cluster of particles.
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A 12.6-kg monkey is hanging by one arm from a branch and swinging on a vertical circle. As an approximation, assume a radial dis
Zinaida [17]

Answer:

a)27.3N

b)150.78N

Explanation:

Having in mind the conservation of energy, as the monkey goes up (gaining potential gravitational energy) the kinetic energy must be reduced, so reducing the velocity of the monkey. So the maximum velocity will be at this lower point with a velocity of 1.36m/s

From this velocity and the radius we can calculate the angular velocity for the monkey center of mass:

w=\frac{1.36m/s}{0.853m} =1.594 /s

with this we can calculate the centripetal force magnitude:

F=m*w^{2} *r=12.6kg*(1.594/s)^{2} *0.853m=27.3N

On the mokey center of mass we have two opposite forces acting, the tension of the arm and the weight, in order for the monkey to continue swinging the resolt of this two forces must be equal to the centripetal force:

T-P=F=>T=F+P

T=27.3N+12.6kg*9.8m/s^{2}=150.78N

8 0
3 years ago
Develop expression for equation for uniform motion in a straight line
frozen [14]
According to cuneiform tablets in the ancient world, straight lines cannot cross, and no motion in the world is not relative. Btw...I KNOW!!! GOT MILK???
4 0
3 years ago
Question 1 of 5<br> In which way are electromagnetic waves different from mechanical waves?
Lina20 [59]

Answer:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

8 0
2 years ago
Read 2 more answers
A crate of mass 50kg is pushed along a floor with a force of 20N for a distance of
PSYCHO15rus [73]

Answer:

F=50kg

D=5m

W=FD

therefore work done is 250Nm

8 0
2 years ago
A ship sets sail from Rotterdam, The Netherlands, intending to head due north at 6.5 m/s relative to the water. However, the loc
sattari [20]

Answer:

Explanation:

velocity of ship with respect to water = 6.5 m/s due north

\overrightarrow{v}_{s,w}=6.5 \widehat{j}

velocity of water with respect to earth = 1.5 m/s at 40° north of east

\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

\overrightarrow{v}_{s,e} = 6.5 \widehat{j}- 1.5\left (Cos40\widehat{i} +Sin40\widehat{j}  \right )

\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

5 0
3 years ago
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