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2 years ago

Given the range (1, 1), (4, 2), (2, -1), with a coordinate transformation of f(x, y) = (x+2, y-3), what is the domain?

Mathematics

1 answer:

pshichka [43]2 years ago

8 0

Answer:

Step-by-step explanation:

I believe it is A. because there are the numbers that equal all together to get that domain.

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3 years ago

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Option 3

The solution for given expression is $\frac{(x - 4)(x - 4)}{(x + 3)(x + 1)}$

<h3><u>Solution:</u></h3>

Given that we have to divide,

$\frac{x^2 -16}{x^2 + 5x + 6} \div \frac{x^2 + 5x + 4}{x^2 -2x - 8}$ ---- (A)

Let us first factorize each term and then solve the sum

Using $a^2 - b^2 = (a + b)(a - b)$

$x^2 -16 = x^2 - 4^2 = (x + 4)(x -4)$ ----- (1)

$x^2 + 5x + 6 = (x + 2)(x + 3)$ ----- (2)

$x^2 + 5x + 4 = (x+1)(x + 4)$ ---- (3)

$x^2 -2x - 8 = (x-4)(x + 2)$ ---- (4)

Now substituting (1), (2), (3), (4) in (A) we get,

$\frac{(x + 4)(x -4)}{(x +2)(x +3)} \div \frac{(x+1)(x+4)}{(x-4)(x +2)}$

To do division with fractions, we turn the second fraction upside down and change the division symbol to a multiplication symbol at the same time. Then we treat this as a multiplication problem, by multiplying the numerators and the denominators separately.

$\frac{(x + 4)(x -4)}{(x +2)(x +3)} \times \frac{(x - 4)(x + 2)}{(x + 1)(x + 4)}$

On cancelling terms we get,

$= \frac{(x -4)(x-4)}{(x + 3)(x + 1)}$

Thus option 3 is correct

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4 years ago

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