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2 years ago

Given the range (1, 1), (4, 2), (2, -1), with a coordinate transformation of f(x, y) = (x+2, y-3), what is the domain?

Mathematics

1 answer:

pshichka [43]2 years ago

8 0

Answer:

Step-by-step explanation:

I believe it is A. because there are the numbers that equal all together to get that domain.

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Click on the graph below to create a quadrilateral with vertices at the following points. (-4,9), (-8,9), (-9,7), (-9, 4)

Shalnov [3]

Given (-4,9) (-8,9),(-9,7,(-9,4)

...

To Find : plot the point and draw quadrilateral

Solution:

(-4,9)

go 4 left of origin and then go 9 up

(-8,9)

go 8 left of origin and then go 8 up

(-9,7)

go 9 left of origin and then go 7 up

(-9,4)

go 9 left of origin and then go join (-4,9) with (-8,9) and (-9,4) 4 up

join (-9,7) with (-8,9) and (-9,4)

Quadrilateral is constructed

4 0

2 years ago

A zoo has 15 toucans and 60 parrots. what is the ratio of the Number of toucans to the number of parrots at the zoo?

Daniel [21]

Answer:

1:4

Step-by-step explanation:

A ratio can be written like this: 15:60, but it can also be written as the fraction 15/60, which can be simplified to 1/4, or 1:4.

5 0

3 years ago

Read 2 more answers

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago

Tell whether it is possible to draw a figure with the given description.

sesenic [268]

Answer:

<h2>in my opinion it is not possible </h2>

Step-by-step explanation:

hope it helps you have a good day

3 0

3 years ago

If the figure is reflected over the x-axis, what are the coordinates of point R?

12345 [234]

Answer:

R' (3,-3)

Step-by-step explanation:

4 0

3 years ago