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2 years ago

A Hartnell governor has two rotating balls, of mass 2.7 kg each. The ball radius is 125 mm in the mean position when the

Engineering

1 answer:

docker41 [41]2 years ago

4 0

Answer:

A Hartnell governor has two rotating balls, of mass 2.7 kg each. The ball radius is 125 mm in the mean position when the

ball arms are vertical and the speed is 150 r.p.m. with the sleeve rising. The length of the ball arms is 140 mm and the

length of the sleeve arms 90 mm. The stiffness of the spring is 7 kN/m and the total sleeve movement is 12 mm from the

mean position. Allowing for a constant friction force of 14 N acting at the sleeve, determine the speed range of the

governor in the lowest and highest sleeve positions. Neglect the obliquity of the ball arms

Explanation:

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A two-dimensional flow field described by

Oduvanchick [21]

Answer:

the answer is

Explanation:

<h2> We now focus on purely two-dimensional flows, in which the velocity takes the form </h2><h2>u(x, y, t) = u(x, y, t)i + v(x, y, t)j. (2.1) </h2><h2>With the velocity given by (2.1), the vorticity takes the form </h2><h2>ω = ∇ × u = </h2><h2> </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y </h2><h2>k. (2.2) </h2><h2>We assume throughout that the flow is irrotational, i.e. that ∇ × u ≡ 0 and hence </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y = 0. (2.3) </h2><h2>We have already shown in Section 1 that this condition implies the existence of a velocity </h2><h2>potential φ such that u ≡ ∇φ, that is </h2><h2>u = </h2><h2>∂φ </h2><h2>∂x, v = </h2><h2>∂φ </h2><h2>∂y . (2.4) </h2><h2>We also recall the definition of φ as </h2><h2>φ(x, y, t) = φ0(t) + Z x </h2><h2>0 </h2><h2>u · dx = φ0(t) + Z x </h2><h2>0 </h2><h2>(u dx + v dy), (2.5) </h2><h2>where the scalar function φ0(t) is arbitrary, and the value of φ(x, y, t) is independent </h2><h2>of the integration path chosen to join the origin 0 to the point x = (x, y). This fact is </h2><h2>even easier to establish when we restrict our attention to two dimensions. If we consider </h2><h2>two alternative paths, whose union forms a simple closed contour C in the (x, y)-plane, </h2><h2>Green’s Theorem implies that </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2></h2><h2></h2>

5 0

3 years ago

Urgent please help!<br> What are non-ferrous metal and ferrous metal?

m_a_m_a [10]

In metallurgy, non-ferrous metals are metals or alloys that do not contain iron in appreciable amounts. Generally more costly than ferrous metals, non-ferrous metals are used because of desirable properties such as low weight, higher conductivity, non-magnetic property or resistance to corrosion

8 0

3 years ago

Cual es el impacto medioambiental del mortero?

ddd [48]

Explanation:

La industria del acero desecha gran cantidad de polvos, los que acopiados al aire libre, sobre el suelo y sometidos a ¡a acción de los agentes climáticos, contaminan el medio ambiente. El propósito del presente trabajo es evaluar el impacto ambiental que produce la incorporación de polvos de acería a matrices de cemento portland, sometidas a condiciones de humedad, presión y temperatura. Se caracterizó químicamente el material de desecho de una acería de Argentina, para identificar los elementos presentes. Por difractometría de rayos X (XRD) se determinaron las estructuras de las sustancias y su grado de oxidación. Se utilizó SEM-EDAX con el propósito de observar forma, tamaño y composición química de las partículas. Se elaboraron diferentes morteros de cemento Portland y se incorporó este material en diferentes porcentajes. Se moldearon probetas normalizadas para realizar ensayos mecánicos, de lixiviación y estudios petrográficos. Se analizó la composición química del agua de curado de las probetas y del líquido obtenido en ensayos de lixiviación. Los resultados permitieron identificar y cuantificar los elementos peligrosos que pueden se incorporados al ambiente y sugerir medidas de prevención.

3 0

3 years ago

What causes decay in the amplitudes of vibration?

worty [1.4K]

Idk honestly just tryna get points.

8 0

3 years ago

Suppose there are 93 packets entering a queue at the same time. Each packet is of size 4 MiB. The link transmission rate is 1.4

Ghella [55]

Answer:

0.19s

Explanation:

Queueing delay is the time a job waits in a queue before it can be executed. it is the difference in time betwen when the packet data reaches it destination and the time when it was executed.

Queueing delay =(N-1) L /2R

where N = no of packet =93

L = size of packet = 4MB

R = bandwidth = 1.4Gbps = 1×10⁹ bps

4 MB = 4194304 Bytes

(93 - 1)4194304 / 2× 10⁹

queueing delay =192937984 ×10⁻⁹

=0.19s

5 0

3 years ago