What is Batch manufacturing?
1 answer:
You might be interested in
Answer:
The channel distance affected by the weir
Yn ( Normal depth ) = 5.71 ft
Yc ( critical depth ) = 4.11 ft
x = 22794 ft
Explanation:
Attached below is a detailed solution to the problem
The channel distance affected by the weir
Yn ( Normal depth ) = 5.71 ft
Yc ( critical depth ) = 4.11 ft
x = 22794 ft
Answer:
m = 1.37 lbm
Explanation:
We are given that;
P1 = 90 psia
T1 = 30°F
From the table i attached, at T = 30°F, entropy, s1 = sf = 0.04752 Btu/lbm.R
We are also given;
P2 = 20 psia.
At this, s2 = s1 = 0.04752 Btu/lbm.R
From the table i attached, sf at 20 psia is; sf = 0.02605 Btu/lbm.R and sfg = 0.19962 Btu/lbm.R
Now, formula for quality of steam at Pressure P2 is;
X2 = (s2 - sf)/sfg
Plugging in the relevant values to obtain;
X2 = (0.04752 - 0.02605)/0.19962
X2 = 0.1076
Now, v2 = vf + x2•vfg
From the table i attached, at 20 psia, vf = 0.01182, vg =2.27772 and vfg = vg - vf = 2.27772 - 0.01182 = 2.2659 ft³/lbm
Thus,
v2 = 0.01182 + 0.1076*2.2659 = 0.2556 ft³/lbm
Now, let's find mass of the refrigerant from, m = V/v2
m = 0.35/0.2556 = 1.37 lbm
