Answer:
Thus, the average velocity is 9.73 m/s.
Explanation:
The velocity is given by the rate of change of position.
initial position, A = (9.2, 3.1) m
final position, B = (72.2, 77.2) m
time, t = 10 s
The velocity is given by
Answer:
B Electrocoagulation.
It is a process that involves the use of high frequency current to cause coagulation usually of protiens in tissues and also the destruction of abnormal tissues making use of the heat generated by the electric current. This tissue could be a tumor or some other kind of lesion.
Explanation:
The passage of electric current through the electrode (second electrode that has been sterilized) in contact with the tissue causes the molecules within them to vibrate. This leads to a sharp increase in the temperature of the tissue due to the heat generated by the electric current. This is what causes the coagulation of the proteins within the tissue and also burns the tissue thereby effectively destroying it.
Electrocoagulation also called electrocautery, electrofulguration, and fulguration.
Explanation:
if u apply more force to an object, it accelerates at a higher rate
Q = I t = 30 x 120 = 3600 C
Answer:
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Explanation:
This scenario can be represented by an arithmetic progression AP.
nth term = a + nd
Where a is the first term given as 2.63 ft.
d is the common difference and is given as 5.3ft.
n is the particular second/time.
To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.
d = nth sum = (n/2)(2a+(n-1)d)
Where n = 10 seconds
a = 2.65 ft
d = 5.3 ft
Substituting the values we have;
d = (10/2)(2×2.65 + (10-1)5.3)
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
