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velikii [3]
3 years ago
10

What needs to remain constant for Boyle's law to hold true?

Physics
2 answers:
bija089 [108]3 years ago
4 0
Boyle's law states that at constant temperature for a fixed mass, the absolute pressure and the volume of a gas are inversely proportional. The law can also be stated in a slightly different manner, that the product of absolute pressure and volume is always constant<span>.

I hope my answer has come to your help. God bless and have a nice day ahead!


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lyudmila [28]3 years ago
3 0
Boyle's law is a gas law which states that pressure and volume of a gas are inversely proportion to each other when temperature is kept constant.
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11. A cyclist accelerates from 0 m/s to 10 m/s in 3 seconds. What is his acceleration ? Is this acceleration higher than that of
Marat540 [252]

a =  \frac{v - u}{t}

v = final velocity

u = initial velocity

t = time taken

the acceleration of the cyclist is

\frac{10 - 0}{3}  = 3.333333....

approximately 3.33 m/s^2

the acceleration of the car is

\frac{40 - 0 }{8}  = 5.0

5.0 m/s^2

5.0 > 3.33 \\ so \:  the \: answer  \: is \: no

6 0
3 years ago
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia
Gala2k [10]

Answer:

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

5 0
3 years ago
Two disks of identical mass but different radii (r and 2r) are spinning on frictionless bearings at the same angular speed ?0, b
cestrela7 [59]

Answer:

Explanation:

Moment of inertia of a disc = 1/2 M R²

Since mass is same for both and radius are r and 2r, their moment of inertia can be in the ratio of 1: 4 . Let them be I and 4I . Angular speed are ω₀ and   - ω₀ .

We shall apply law of conservation of angular momentum .

initial total angular momentum

I x ω₀ - 4I x ω₀ = - 3Iω₀

Let final common angular momentum be ω

total final angular momentum = ( I + 4I ) ω

Applying law of conservation of angular momentum

( I + 4I ) ω =  - 3Iω₀

ω = - 3 / 5 ω₀ .

b )

Initial total rotational K E

= 1/2 I ω₀² + 1/2 4I ω₀²

= 1/2 x5I ω₀²

Final total rotational K E

= 1/2 ( I + 4I ) ( - 3 / 5 ω₀ )²

= 1/2 x 9 / 5 I ω₀²

= 9 / 10I ω₀²

change in rotational kinetic energy = 9 / 10I ω₀² - 1/2 x5I ω₀²

(9/10 - 5/2) xI ω₀²

=( .9 - 2.5 )I ω₀²

= - 1.6 I ω₀² Ans

8 0
3 years ago
Measurement conversions [metric to metric] 568 cm = m​
Trava [24]

Answer:

5.68 meters

Explanation:

hope this helps!

7 0
3 years ago
A man is doing push-ups. he has a mass of 68 kg and his center of gravity is located at a horizontal distance of 0.70 m from his
lidiya [134]
Mass m = 68 kg
center of gravity from his palms x = 0.7 m
center of gravity from his feet x ' = 1 m
forces exerted by the floor on his palms and feet are F and F ' respectively.

with respect to palms :---------------------

( F*0 ) - (W * x ) + [ F ' * (x+x') ] = 0

             -mg*0.7 + F ' * 1.7 = 0    where W = weight = mg

F ' * 1.7 = mg * 0.7

          F ' = mg * 0.7 / 1.7

               = 68 *9.8 * ( 0.7 / 1.7 )

               = 274.4 N

with respect to feet :--------------------

( F ' * 0 ) -( W* x ' ) + [F * ( x + x') ] = 0

                -mg*1 + [ F * 1.7 ]= 0

                                 F = mg / 1.7

                                    = 392 N
7 0
3 years ago
Read 2 more answers
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