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Alisiya [41]
3 years ago
11

List in order from smallest to largest the grain sizes used to describe detrital rocks.

Physics
2 answers:
Masja [62]3 years ago
7 0
If there is more to the problem
I can help you
earnstyle [38]3 years ago
3 0
Where is the rest of the problem
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Question 4 of 10
anzhelika [568]
The answer is c. The particles of b are more closely packed
5 0
3 years ago
Use the table below to answer the following questions. Substance Specific Heat (J/g•°C) water 4.179 aluminum 0.900 copper 0.385
lbvjy [14]

1. -8.78 \cdot 10^5 J

The energy lost by the water is given by:

Q=m C_s \Delta T

where

m = 3.0 kg = 3000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

\Delta T=10.0C-80.0C=-70.0 C is the change in temperature

Substituting,

Q=(3000 g)(4.179 J/gC)(-70.0 C)=-8.78 \cdot 10^5 J

2. 3.24 \cdot 10^4 J

The energy added to the aluminium is given by:

Q=m C_s \Delta T

where

m = 0.30 kg = 300 g is the mass of aluminium

Cs = 0.900 J/g•°C is the specific heat

\Delta T=150.0 C-30.0C =120.0 C is the change in temperature

Substituting,

Q=(300 g)(0.900 J/gC)(120.0 C)=3.24 \cdot 10^4 J

3a. -5.6^{\circ}C

The temperature change of the water is given by

\Delta T=\frac{Q}{m C_s}

where

Q = -232 kJ=-2.32\cdot 10^5 J is the heat lost by the water

m=10.0 kg=10000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

Substituting,

\Delta T=\frac{-2.32\cdot 10^5 J}{(10000g)(4.179 J/gC)}=5.6^{\circ}C

3b. +10.2^{\circ}C

The temperature change of the copper is given by

\Delta T=\frac{Q}{m C_s}

where

Q = 1.96 kJ=1960 is the heat added to the copper

m= 500 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

Substituting,

\Delta T=\frac{1960 J}{(500g)(0.385 J/gC)}=10.2^{\circ}C

4. 42.9 g

The mass of the water sample is given by

m=\frac{Q}{C_S \Delta T}

where

Q=4300 J is the heat added

\Delta T=39 C-15 C=24C is the temperature change

Cs = 4.179 J/g•°C is the specific heat

Substituting,

m=\frac{4300 J}{(4.179 J/gC)(24 C)}=42.9 g

5. 115.5 J

The heat used to heat the copper is given by:

Q=m C_s \Delta T

where

m = 5.0 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

\Delta T=80.0 C-20.0C =60.0 C is the change in temperature

Substituting,

Q=(5.0 g)(0.385 J/gC)(60.0 C)=115.5 J

6. 0.185 J/g•°C

The specific heat of iron is given by:

C_s = \frac{Q}{m \Delta T}

where

Q = -47 J is the heat released by the iron

m = 10.0 g is the mass of iron

\Delta T=25.0-50.4 C=-25.4 C is the change in temperature

Substituting,

C_s = \frac{-47 J}{(10.0 g)(-25.4 C)}=0.185 J/gC

8 0
4 years ago
you are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what
grigory [225]

You are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what

--------------------------

relative to sidewalk you are moving with the driver

4 0
4 years ago
A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?
olga55 [171]

Answer:

17.6 m/s²

Explanation:

Given:

v_{f} = 90 m/s (final velocity)

v_{i} = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

a_{avg} = Δv / Δt

We can find Δv by doing

Δv = v_{f} - v_{i}

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

a_{avg} = Δv / Δt

a_{avg} = \frac{88m/s}{5/s}

acceleration = 17.6 m/s^{2}

4 0
3 years ago
Light year is a unit of?
IrinaVladis [17]
Light year is the unit of distance. It is the distance that an object travels in one year with the speed of light.

In short, Your Answer would be "Distance"

Hope this helps!
3 0
3 years ago
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