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Alisiya [41]
3 years ago
11

List in order from smallest to largest the grain sizes used to describe detrital rocks.

Physics
2 answers:
Masja [62]3 years ago
7 0
If there is more to the problem
I can help you
earnstyle [38]3 years ago
3 0
Where is the rest of the problem
You might be interested in
What is the rate of acceleration due to gravity on Earth?
Katena32 [7]

Answer:

Negative 9.8 meters per second squared

Explanation:

The negative is for the direction (down, towards the center of the earth). Often this can be estimated as -10 m/s^2 to make calculations easier.

3 0
3 years ago
Free Fall: A rock is thrown directly upward from the edge of a flat roof of a building that is 56.3 meters tall. The rock misses
Slav-nsk [51]

Answer:

v₀₁= 5.525 m / s

Explanation

Freefall Formulas :

The sign of acceleration due to gravity  (g) is positive if the object is going down and negative if the object is going up.

vf= v₀+gt  

vf²=v₀²+2*g*h

h= v₀t+ (1/2)*g*t²

Where:  

h: hight in meters (m)    

t : time in seconds (s)

v₀: initial speed in m/s  

vf: final speed in m/s  

g: acceleration due to gravity in m/s²

Kinematics of the rock from the starting point with vo until it reaches its maximum height:

vf₁= v₀₁-gt₁  :vf₁ =0 to maximum height

0= v₀₁-gt₁

v₀₁ = g*t₁

t₁ =v₀₁ / g      Equation (1)

vf₁²= v₀₁²-2*g*h₁   : vf₁ =0 to maximum height

0 = v₀₁²-2*g*h₁

2*g*h₁ = v₀₁²

h₁ = (v₀₁²)/(2g)   Equation (2)

Kinematics of the rock when it falls from the maximum height until it touches the floor

h₂= v₀₂t+ (1/2)*g*t₂²  v₀₂=vf₁ =0

h₂= 0+ (1/2)*g*t₂²

h₂= (1/2)*g*t₂²   Equation (3)

Equation that relates h₁ to h₂

h₂=  h₁ + 56.3  ,  h₁ = (v₀₁²)/(2g)

h₂= (v₀₁²)/(2g) + 56.3  Equation (4)

Equation that relates t₁ to t₂

t₁ + t₂ =4 s

t₂ =4 -t₁

t₂ =4 -(v₀₁/g )

Calculation of v₀₁

We replace equation 4 and equation 5 in equation 3

(v₀₁²)/(2g) + 56.3 = (1/2)*g*(4 -(v₀₁/g ) )²

(v₀₁²)/(2g) + 56.3 = (1/2)*g* (16 - 2*4*(v₀₁/g )+((v₀₁/g )²)

we eliminate (v₀₁²)/(2g) on both sides of the equation

56.3 = (1/2)*g* (16 - 2*4*(v₀₁/g ))

56.3 = 78.4 - 4*v₀₁

4*v₀₁ =78.4-56.3

v₀₁= (78.4-56.3) / ( 4)

v₀₁= 5.525 m / s

7 0
3 years ago
Describe how energy is transferred from the sun to producers and then to consumers
Sphinxa [80]
Producers to primary consumers to secondary consumers to tertiary consumers to carnivores
7 0
3 years ago
The y component of the electric field of an electromagnetic wave travelling in the +x direction through vacuum obeys the equatio
notsponge [240]

Answer:

λ =8.57 μ m

Explanation:

Given that

Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C

Standard form  

Ey=Eo cos[k x-ωt]  N/C

By comparing the given equation with the standard wave equation

Eo = 375 N/C

ω  = 2.20 × 10¹⁴ rad/s

We know that ω = 2 π f

f=\dfrac{\omega}{2\pi }

f=\dfrac{2.2\times 10^{14}}{2\pi }\ Hz

f=3.50×10¹³ Hz

We know that the velocity given as

V = f λ

λ =Wavelength

V=Speed = 3 x 10⁸ m/s

\lambda =\dfrac{V}{f }

\lambda =\dfrac{3\times 10^8}{3.5\times 10^{13}}\ m

λ =0.00000857 m              ( 1 μ m = 10⁶ m)

λ =8.57 μ m

8 0
3 years ago
An 1800-kg truck pulls a 710-kg trailer away from a stoplight with an acceleration of 1.20 m/s2 . Part A What is the net force e
faust18 [17]

Answer:

F = 852 N

Explanation:

We apply Newton's second law to the trailer :

F = m*a   Formula (1)

F : net force exerted by the truck on the trailer Newtons (N)

m : mass of the trailer in kilograms (kg)

a : acceleration of the trailer in meters over second square (m/s²)

Data

a=1.20 m/s² : acceleration of the trailer

m=710 kg : mass of the trailer

We replace data in the   Formula (1)  to calculate the net force exerted by the truck on the trailer

F = (710 kg)*(1.20 m/s²)

F = 852 N

8 0
2 years ago
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