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Alisiya [41]
3 years ago
11

List in order from smallest to largest the grain sizes used to describe detrital rocks.

Physics
2 answers:
Masja [62]3 years ago
7 0
If there is more to the problem
I can help you
earnstyle [38]3 years ago
3 0
Where is the rest of the problem
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The driver of a car slams on the brakes, causing the car to slow down at a rate of
sdas [7]

Answer:

A. The time taken for the car to stop is 3.14 secs

B. The initial velocity is 81.64 ft/s

Explanation:

Data obtained from the question include:

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

Final velocity (V) = 0

Time (t) =?

Initial velocity (U) =?

A. Determination of the time taken for the car to stop.

Let us obtain an express for time (t)

Acceleration (a) = Velocity (V)/time(t)

a = V/t

Velocity (V) = distance (s) /time (t)

V = s/t

a = s/t^2

Cross multiply

a x t^2 = s

Divide both side by a

t^2 = s/a

Take the square root of both side

t = √(s/a)

Now we can obtain the time as follow

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

Time (t) =..?

t = √(s/a)

t = √(256/26)

t = 3.14 secs

Therefore, the time taken for the car to stop is 3.14 secs

B. Determination of the initial speed of the car.

V = U + at

Final velocity (V) = 0

Deceleration (a) = –26ft/s2

Time (t) = 3.14 sec

Initial velocity (U) =.?

0 = U – 26x3.14

0 = U – 81.64

Collect like terms

U = 81.64 ft/s

Therefore, the initial velocity is 81.64 ft/s

7 0
3 years ago
explain why a high-speed collision between two cars would cause more damage than a low-speed collision between the same two cars
9966 [12]
The force equation can easily prove this.  F=ma.  This states that the force on an object is equal to mass times acceleration.  If the mass stays the same and the velocity of the cars increases than that means there is a larger force.  This is because in both cases the cars are stopping in almost an instant and the times of the crashes are theoretically identical.  Acceleration is the change in velocity over time.  If the velocity is higher with the same amount of time than that means there is a higher acceleration.  If you plug a higher acceleration into the force equation then you wind up with a higher force and in turn a more damaging collision.
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8 0
3 years ago
Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr
slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

W = F_{total} .d

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W  = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} .d =\frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}

F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

F_{sprinter} = F_{total} + F_{wind}  = 39.7 + 30 = 69.68 N

7 0
3 years ago
Read 2 more answers
A 5 kg mass is accelerated at a rate of 2.5 m/s/s. what is the force that is exerted on this object
Sav [38]

Answer:

<h2>12.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5 × 2.5

We have the final answer as

<h3>12.5 N</h3>

Hope this helps you

3 0
3 years ago
PLEASE PLEASE PLEASE HELP
lakkis [162]

Answer:

Rain came along with lower temps

Explanation:

There was no rain on the warmer days

There were more clouds as the week went on

and the temp decreased during the week so rain came with lower temps is the only one that can be correct

5 0
2 years ago
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