1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
3 years ago
5

A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is

65% salt and Solution B is 90% salt. She wants to obtain 120 ounces of a mixture that is 75% salt. How many ounces of each solution should she use?
Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

  • 48 oz of 90% (B)
  • 72 oz of 65% (A)

Step-by-step explanation:

The amount of salt in the mixture is the sum of the amounts of salt in the constituents. Those amounts are found by multiplying the quantity of solution by the percentage that is salt.

__

Let x represent the quantity of 90% salt solution B, in ounces. Then the number of ounces of salt in the mix is ...

  0.90x +0.65(120 -x) = 0.75(120)

  0.25x = 0.10(120) . . . . . . subtract 0.65(120) and simplify

  x = 48 . . . . . . . . . . . . . divide by 0.25

  120 -x = 72 . . . . . . . amount of 65% solution A

She should use 48 ounces of 90% solution B, and 72 ounces of 65% solution A.

You might be interested in
In an arithmetic​ sequence, the nth term an is given by the formula an=a1+(n−1)d​, where a1 is the first term and d is the commo
Dmitry_Shevchenko [17]

Answer:

a_{10} = \frac{10}{65536}

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

a_{3} - a_{2} = a_{2} - a_{1}

We have that:

a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}

a_{3} - a_{2} = a_{2} - a_{1}

\frac{5}{2} - 10 = 10 - 40

\frac{-15}{2} \neq -30

This is not an arithmetic sequence.

This sequence is geometric if:

\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}

\frac{\frac{5}[2}}{10} = \frac{10}{40}

\frac{5}{20} = \frac{1}{4}

\frac{1}{4} = \frac{1}{4}

This is a geometric sequence, in which:

The first term is 40, so a_{1} = 40

The common ratio is \frac{1}{4}, so r = \frac{1}{4}.

We have that:

a_{n} = a_{1}*r^{n-1}

The 10th term is a_{10}. So:

a_{10} = a_{1}*r^{9}

a_{10} = 40*(\frac{1}{4})^{9}

a_{10} = \frac{40}{262144}

Simplifying by 4, we have:

a_{10} = \frac{10}{65536}

3 0
4 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

7 0
3 years ago
What is an example of a non-statistical question? Question 1 is because of winn dixie your favorite book
lozanna [386]

Answer:

examples of non-statistical questions are: how old are you?

Step-by-step explanation:

Non-Statistical Questions. The next type of question is the non-statistical question. This is the type of question that only has one answer. This one answer also doesn't change. You don't need to gather several points of data to answer the question.

7 0
4 years ago
Read 2 more answers
HELP PLEASEEE!!
Luden [163]

\left[\begin{array}{ccc}2&6&3\\-5&1&4\end{array}\right]

R1 ÷ 2  = \left[\begin{array}{ccc}1&3&1.5\\-5&1&4\end{array}\right]

R2 ÷ -5 = \left[\begin{array}{ccc}1&3&1.5\\1&-0.2&-0.8\end{array}\right]

R2: R1 - R2  = \left[\begin{array}{ccc}1&3&1.5\\0&3.2&2.3\end{array}\right]

R2 ÷ 3.2 =  \left[\begin{array}{ccc}1&3&1.5\\0&1&0.71875\end{array}\right]

R1: R1 - 3R2 = \left[\begin{array}{ccc}1&0&0.65625\\0&1&0.71875\end{array}\right]

Answer: x = 0.65625, y = 0.71875

8 0
3 years ago
How can I solve this?
Eva8 [605]

Answer:

they are congruent so 47 is also the measurement for its corresponding angle(aka the corner that doesn't have a variable)

and in a triangle, interior angles add to 180 so 47+x+y=180

90 + 43 = 133

+47= 180

so your answer is a

hope this helps!!

8 0
3 years ago
Other questions:
  • How can you show two objects are proportional with a table,graph, and a equation?
    9·1 answer
  • In which number does the 6 have a value that is one tenth the value of the 6 in 34, 761
    12·1 answer
  • Can you show the work
    8·1 answer
  • Which shape is both a rectangle and a square?<br> please help i’ll rate you brainliest
    5·2 answers
  • If Aldo puts 400 into a savings account that paid an interest rate of 5.4 percent What was the total amount in his account at th
    14·1 answer
  • Mallory began a new job at an amusement park 4 weeks ago. She worked 13 hours during the first week, 22 hours during the second
    6·2 answers
  • Write an equation of a line that passes thought he point (-5,2) And is parallel to the line represent by the equation 2x + 5y =
    12·1 answer
  • For the equation -4y = 8x whay is the constant of variation
    6·1 answer
  • Find the value of x.<br> A. About 57.6<br> B. About 42.6<br> C. About 12.6<br> D. About 27.6
    5·1 answer
  • You have to spend less than $500 at the mall. Each pair of pants costs $25 and each shirt costs $10. Write an inequality to repr
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!