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3 years ago

10

Write an equation of the line that passes through the point (2, 3) and is perpendicular to the line x = -1.

2 answers:

Sedbober [7]3 years ago

7 0

Answer:

B)Y=3

Step-by-step explanation:

PSYCHO15rus [73]3 years ago

3 0

Answer:

y=3

Step-by-step explanation:

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A nick on the edge of a CD rotates to (−6, 5) during one song when represented graphically.

Allisa [31]

By definition, the sine of an angle is given by:
$sin \alpha = \frac{C.O}{h}$
Where,
C.O: opposite leg
h: hypotenuse
The hypotenuse is given by:
$h = \sqrt{(-6)^2+(5)^2}$
$h = \sqrt{(61}$
So, replacing values we have:
$sin \alpha = \frac{5}{\sqrt{61}}$
Rewriting we have:
$sin \alpha = \frac{5\sqrt{61}}{61}$
Answer:
the sine value of this function is:
A)5 times square root 61 over 61

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3 years ago

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The original quantity is 10 and the new quantity is 13. What is the percent change?

Leya [2.2K]

3 is 13 more than 10, and 3 is 30% of 10, so 30% im pretty sure

6 0

2 years ago

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0.0215 has ____ significant figures

shepuryov [24]

Answer:

has 3 significant figures

Step-by-step explanation:

because zeros are counted if they are between the numbers

7 0

3 years ago

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Ten years ago in Louisiana, schools averaged 182 pupils for every 10 teachers. Write a ratio for this problem in 3 different way

Anettt [7]

182:10

182/10

182 to 10

6 0

2 years ago

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

LuckyWell [14K]

Answer:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

$df = n_1 +n_2 -2 = 10+15-2= 23$

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

$\bar X_1 = 1085$ sample mean for group 1

$\bar X_2 = 1034$ sample mean for group 2

$n_1 = 10$ sample size for group 1

$n_2 = 15$ sample size for group 2

$s_1 = 52$ sample deviation for group 1

$s_2 = 61$ sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: $\mu_1= \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

And the statistic is given by:

$t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

And replacing we got:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 10+15-2= 23$

And the p value would be:

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0

3 years ago